Solve: (6x^2+5x-1) ÷ (2x+1)

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Asked 12/4/2011 6:52:51 PM

Updated 12/5/2011 5:30:38 AM

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Asked 12/4/2011 6:52:51 PM

Updated 12/5/2011 5:30:38 AM

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The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.

Added 12/5/2011 5:30:38 AM

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Confirmed by andrewpallarca [8/13/2014 6:31:03 PM]

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A ______________ is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0

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Updated 8/17/2014 6:25:04 PM

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A quadratic equation is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0.

Added 12/4/2011 6:34:54 PM

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Confirmed by andrewpallarca [8/17/2014 6:25:05 PM]

find x: 3(x-5)=0 **Weegy:** 3(x-5)=0; 3x - 15 = 0, 3x = 15, x = 15/3, x = 5 (More)

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Solve: (6x^2+5x-1) ÷ (2x+1) **Weegy:** (6x^2+5x-1) ÷ (2x+1)
=((x+1)(6x-1))/(2x+1) (More)

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Updated 12/5/2011 5:30:10 AM

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My answer is not wrong. You can't flag it. Please, reconsider your question.

Added 12/4/2011 11:50:15 PM

The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.

Added 12/5/2011 5:30:10 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [8/17/2014 6:29:44 PM]

What is a Network Address? **Weegy:**
A network address is an identifier for a node or network interface of a telecommunications network.
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