Solve: (6x^2+5x-1) ÷ (2x+1)
Updated 12/5/2011 5:30:38 AM
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Original conversation
User: Solve: (6x^2+5x-1) ÷ (2x+1)

Weegy: Is it a quadratic equation?

User: No please divide the polynomials

Weegy: 6x^2 + 2.5x+1

Updated 12/5/2011 5:30:38 AM
This conversation has been flagged as incorrect.
Rating
3
The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
Confirmed by andrewpallarca [8/13/2014 6:31:03 PM]

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The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
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