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Solve and show all work. 10-x=-3x-6
10-x=-3x-6; -x + 3x = -6 - 10; 2x = -16; x = -16/2; x = -8
Expert answered|jtlara074|Points 0|
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Asked 6/18/2012 9:40:59 AM
Updated 4/28/2014 4:50:23 PM
0 Answers/Comments
This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [4/28/2014 4:50:21 PM], Confirmed by andrewpallarca [4/28/2014 4:50:23 PM]
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Solve and show all the steps on how you got your answer. 10-x=-3x-6.
Weegy: 10-x=-3x-6; -x + 3x = -6 - 10; 2x = -16; x = -16/2; x = -8 (More)
Question
Expert Answered
Updated 4/13/2014 9:07:03 AM
0 Answers/Comments
Simplify: -3(2z + 7) a. -6z + 7 b. -6z - 21 c. -6z + 21 d. -27z
Question
Not Answered
Updated 8/5/2014 11:43:58 PM
1 Answer/Comment
-3(2z + 7) = -6z - 21
Added 8/5/2014 11:43:58 PM
This answer has been confirmed as correct and helpful.
Simplify: -3(2z + 7)
Weegy: -3(2z + 7) = -6z - 21 (More)
Question
Expert Answered
Updated 5/1/2014 12:58:49 AM
0 Answers/Comments
Simplify: 3(x + 4) - 2(x - 2) a. x + 8 b. -5x + 16 c. x + 16 d. 5x + 16
Weegy: 3(x+4)-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply 3 by each term inside the parentheses (x+4). 3(x)+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply 3 by the x inside the parentheses. 3*x+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply 3 by x to get [ 3x. 3x+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply 3 by the 4 inside the parentheses. 3x+3*4-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply 3 by 4 to get 12. 3x+12-2(x-2)*ax+8b-5x+16cx+16dx+16 Multiply -2 by each term inside the parentheses (x-2). 3x+12-2(x)-2(-2)*ax+8b-5x+16cx+16dx+16 Multiply -2 by the x inside the parentheses. 3x+12-2*x-2(-2)*ax+8b-5x+16cx+16dx+16 Multiply -2 by x to get -2x. 3x+12-2x-2(-2)*ax+8b-5x+16cx+16dx+16 Multiply -2 by the -2 inside the parentheses. 3x+12-2x-2*-2*ax+8b-5x+16cx+16dx+16 Multiply -2 by -2 to get 4. 3x+12-2x+4*ax+8b-5x+16cx+16dx+16 Multiply 4 by ax to get 4ax. 3x+12-2x+4ax+8b-5x+16cx+16dx+16 According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both 3x and -2x. (3-2)x+12+4ax+8b-5x+16cx+16dx+16 To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 3 and -2 and give the result the same sign as the integer with the greater absolute value. (1)x+12+4ax+8b-5x+16cx+16dx+16 Remove the parentheses. x+12+4ax+8b-5x+16cx+16dx+16 According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both x and -5x. (1-5)x+12+4ax+8b+16cx+16dx+16 To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 1 and -5 and give the result the same sign as the integer with the greater absolute value. (-4)x+12+4ax+8b+16cx+16dx+16 Remove the parentheses. -4x+12+4ax+8b+16cx+16dx+16 Add 16 to 12 to ... (More)
Question
Expert Answered
Updated 6/24/2012 11:10:49 PM
4 Answers/Comments
c. x + 16

3(x + 4) - 2(x - 2) = 3x + 12 - 2x + 4 = x + 16.

Source:
Added 6/23/2012 6:25:25 PM
This answer has been confirmed as correct and helpful.
Rated bad by John@evang, Confirmed by jeifunk [6/30/2014 12:54:32 AM]
Sorry for the error.
Added 6/24/2012 4:27:26 PM
This answer has been flagged as incorrect.
Flagged by jeifunk [6/30/2014 12:53:41 AM]
Ans-C: x + 16 =
3(x+4)-2(x-2)=
3x + 12 - 2x + 4=
collect the like terms.
3x - 2x + 12 + 4=
x + 16 .
Added 6/24/2012 7:24:15 PM
This answer has been flagged as incorrect.
Confirmed by jeifunk [6/30/2014 12:54:19 AM], Unconfirmed by jeifunk [6/30/2014 12:54:28 AM], Flagged by jeifunk [6/30/2014 12:54:34 AM], Unflagged by jeifunk [6/30/2014 12:54:45 AM], Flagged by jeifunk [6/30/2014 12:54:48 AM]
c 3x+12-2x+4=x+16
Added 6/24/2012 11:10:49 PM
This answer has been flagged as incorrect.
Flagged by jeifunk [6/30/2014 12:54:38 AM]
Combine like terms: 4x + 2y - 3x + 7y
Weegy: 4x + 2y - 3x + 7y = x + 9y (More)
Question
Expert Answered
Updated 4/28/2014 4:49:02 PM
0 Answers/Comments
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