Multiply (y^2-8)(4y^2-3y+1)

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Asked 7/17/2011 4:18:27 PM

Updated 10/29/2014 6:34:00 PM

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Flagged by andrewpallarca [10/29/2014 6:34:00 PM]

Expert answered|emerhope|Points 91|

Question|Rated bad

Asked 7/17/2011 4:18:27 PM

Updated 10/29/2014 6:34:00 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by andrewpallarca [10/29/2014 6:34:00 PM]

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(y^2 - 8)(4y^2 - 3y + 1)

= 4y^4 - 3y^3 + y^2 - 32y^2 + 24y - 8

= 4y^4 - 3y^3 - 31y^2 + 24y - 8

= 4y^4 - 3y^3 + y^2 - 32y^2 + 24y - 8

= 4y^4 - 3y^3 - 31y^2 + 24y - 8

Added 10/29/2014 6:33:58 PM

This answer has been confirmed as correct and helpful.

Multiply and simplify n^6*n^7
**Weegy:** 16+n (More)

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Expert Answered

Updated 6/16/2014 12:01:36 PM

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n^6*n^7 = n^(6+7) = n^13

Added 6/16/2014 12:01:36 PM

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Express using a positive exponent x^-7 **Weegy:** 14 (More)

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Updated 10/29/2014 6:35:09 PM

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x^-7 = 1/x^7

Added 10/29/2014 6:35:04 PM

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Divide and simplify 3^7/3^2=?

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Updated 6/27/2014 10:17:56 AM

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3^7/3^2 = (3*3*3*3*3*3*3/3*3)

= 2,187/9 = 243

= 2,187/9 = 243

Added 6/27/2014 10:17:56 AM

This answer has been confirmed as correct and helpful.

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