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Which group was the first to unify much of Mesopotamia and create a true empire? A. Egyptians B. Akkiadians C. Sumerians D. Eridu
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Asked 10/4/2012 6:24:58 AM
Updated 11/26/2015 12:11:55 AM
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Edited by Andrew. [11/26/2015 12:11:53 AM], Flagged by Andrew. [11/26/2015 12:11:55 AM]
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User: Which group was the first to unify much of Mesopotamia and create a true empire? A. Egyptians B. Akkiadians C. Sumerians D. Eridu

Weegy: C.Sumerians
Expert answered|rocketmail|Points 313|

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Asked 10/4/2012 6:24:58 AM
Updated 11/26/2015 12:11:55 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by Andrew. [11/26/2015 12:11:53 AM], Flagged by Andrew. [11/26/2015 12:11:55 AM]
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Akkiadians were the first to unify much of Mesopotamia and create a true empire.
Added 11/26/2015 12:11:53 AM
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The overnight temperature falls 16 degrees then rises 5 degrees. What was the overall change in temperature? degrees
Weegy: The answer is 11 degrees. User: Simplify -8(5b - 2) a -8b + 16 b -40b + 16 c -13b - 10 d -40b - 2 Weegy: A. (ab^(2))^(5) Expand the exponent (5) to the expression. a^(5)b^(2*5) Multiply 2 by 5 to get [ 10. a^(5)b^(10) B.(2x)^(2)(2x)^(4) Expand the exponent (2) to the expression. 2^(2)x^(2)(2x)^(4) Squaring a number is the same as multiplying the number by itself (2*2). In this case, 2 squared is 4. 4x^(2)(2x)^(4) Expand the exponent (4) to the expression. (4x^(2))*2^(4)x^(4) Raising a number to the 4th power is the same as multiplying the number by itself 4 times. In this case, 2 raised to the 4th power is 16. (4x^(2))*16x^(4) Multiply 16x^(4) by each term inside the parentheses. 64x^(6) C. (m^(3)n^(2))^(3) Expand the exponent (3) to the expression. m^(3*3)n^(2*3) Multiply 3 by 3 to get 9. m^(9)n^(2*3) Multiply 2 by 3 to get 6. m^(9)n^(6) D. 2^(5)*(2^(-7))/(2^(3)) Raising a number to the 5th power is the same as multiplying the number by itself 5 times. In this case, 2 raised to the 5th power is 32. 32*(2^(-7))/(2^(3)) To divide 2^(-7) by 2^(3), subtract the denominator exponent from the numerator exponent. 32*2^(-7-3) Subtract 3 from -7 to get -10. 32*2^(-10) Remove the negative exponent by rewriting 2^(-10) as (1)/(2^(10)). A negative exponent follows the rule a^(-n)=(1)/(a^(n)). 32*(1)/(2^(10)) Raising a number to the 10th power is the same as multiplying the number by itself 10 times. In this case, 2 raised to the 10th power is 1024. 32*(1)/(1024) Cancel the common factor of 32 from the first term 32 and the denominator of the second term (1)/(1024). 1*(1)/(32) Multiply 1 by (1)/(32) to get (1)/(32). (1)/(32) The approximate value of 2^(5)*(2^(-7))/(2^(3)) is 0.03. 0.03 ] (More)
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Updated 6/4/2014 9:26:51 PM
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-8(5b - 2) = -40b + 16
Added 6/4/2014 9:26:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/26/2014 7:56:10 AM]
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