Find the slope of the line that passes through the points (3, 6) and (5, 3). A.-3/2 B.3/2 C.2/3
A.-3/2
Question
Updated 324 days ago|11/4/2017 8:39:39 AM
Edited by Masamune [11/4/2017 8:38:49 AM]
Rating
3
The slope of the line that passes through points (3, 6) and (5, 3) is -3/2.

m = (3 - 6)/(5 - 3)
m = -3/2
Added 324 days ago|11/4/2017 8:39:39 AM

Questions asked by the same visitor
Find the slope of the line that passes through the points (0, 0) and (-2, -3). A.2/3 B.3/2 C.-3/2
Weegy: Simplifying Ax + By = C Solving xA + yB = C Solving for variable 'x'. Move all terms containing x to the left, [ [ all other terms to the right. Add '-1yB' to each side of the equation. xA + yB + -1yB = C + -1yB Combine like terms: yB + -1yB = 0 xA + 0 = C + -1yB xA = C + -1yB Divide each side by 'A'. x = A-1C + -1yA-1B Simplifying x = A-1C + -1yA-1B ] ] (More)
Question
Updated 1/28/2014 2:45:52 PM
The slope of the line that passes through (0, 0) and (-2, -3) is:
3/2

Find the slope of the line that passes through the points (3, 6) and (5, 3). A.-3/2 B.3/2 C.2/3
Question
Updated 7/28/2014 1:22:28 PM
The slope of the line that passes through the points (3, 6) and (5, 3) is -3/2. m = (3-6)/(5-3); m = -3/2
Confirmed by yumdrea [7/28/2014 11:05:59 PM]
Find the slope of the line passing through the points (3, 8) and (-2, 5). A.3 B.3/5 C.13
Weegy: The slope of the line passing through the points (3, 8) and (-2, 5) is 3/5. m = (5 - 8)/(-2 - 3) ; m = -3/-5 ; m = 3/5 (More)
Question
Updated 125 days ago|5/22/2018 2:28:52 AM
standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x - 2y = 6
Weegy: The answer is y=(x)/(2)+5. [ Here is the steps for solving such a problem: x-2y=6_(-2,4) Since x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting x from both sides. -2y=-x+6 Divide each term in the equation by -2. -(2y)/(-2)=-(x)/(-2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. -(-(2y)/(2))=-(x)/(-2)+(6)/(-2) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. -*-(2y)/(2)=-(x)/(-2)+(6)/(-2) Cancel the common factor of 2 in -(2y)/(2). -*( 2 y)/( 2 )=-(x)/(-2)+(6)/(-2) Remove the common factors that were cancelled out. -*-y=-(x)/(-2)+(6)/(-2) Multiply - by -y to get y. y=-(x)/(-2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. y=-(-(x)/(2))+(6)/(-2) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. y=-*-(x)/(2)+(6)/(-2) Multiply - by -x to get x. y=(x)/(2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. y=(x)/(2)-((6)/(2)) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. y=(x)/(2)-(6)/(2) Cancel the common factor of 2 in -(6)/(2). y=(x)/(2)-(^(3) 6 )/( 2 ) Remove the common factors that were cancelled out. y=(x)/(2)-3 To find the slope and y intercept, use the y=mx+b formula where m=slope and b is the y intercept. y=mx+b Using the y=mx+b formula, m=(1)/(2). m=(1)/(2) To find an equation that is parallel to x-2y=6, the slopes must be equal. ] (More)
Question
Updated 10/25/2011 12:22:23 AM
y=(1/2)x+6 is the standard form equation of the line that passes through (-2, 4) and is parallel to x - 2y = 6.
Confirmed by andrewpallarca [7/22/2014 4:01:26 PM]
How can you rate me bad when the answer is correct. What is would be the standard form...
@thederby the standard form is y=mx+b so the correct equation should be y=(1/2)x+6, where m=1/2 and b=6. your answer y=(x)/(2)+5 is incorrect. the y-intercept "b" should be equal to 6 not 5. ref:
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