Question and answer
Evaluate the following expression. 7^0
7^0 = 1 Anything to the power of zero equals 1.
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Asked 6/22/2011 10:35:03 AM
Updated 2/17/2014 6:53:26 PM
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7^0 = 1
Anything to the power of zero equals 1.
Added 2/17/2014 6:53:26 PM
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Questions asked by the same visitor
9a^4 - b^2
Question
Not Answered
Updated 8/7/2014 8:44:05 AM
1 Answer/Comment
9a^4 - b^2 = (3a^2 - b) (3a^2 + b)
Added 8/7/2014 8:20:36 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/7/2014 8:29:52 AM]
Factor -x2y2 + x4 + 9y2 - 9x2
Weegy: (-4 + x^2) (x^2 - y^2). Please rate the answer. User: Factor 360t + 10t3 - 120t2. (More)
Question
Expert Answered
Updated 6/11/2014 12:39:37 AM
2 Answers/Comments
-x^2y^2 + x^4 + 9y^2 - 9x^2
= x^2(x^2 - y^2) - 9(x^2 - y^2)
= (x^2 - y^2)(x^2 - 9)
= (x + y)(x - y)(x + 3)(x - 3)
Added 6/11/2014 12:38:44 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/11/2014 12:55:28 AM]
360t + 10t^3 - 120t^2
= 10t(36 + t^2 - 12t)
= 10t(t - 6)^2
Added 6/11/2014 12:39:37 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/11/2014 12:55:52 AM]
(5x2 + 2x - 3)(x - 1) answer choices are: A. 5x - 2x2 + 3x4 B. 5x2 - 5x - 1 C. 7x3 + 6x2 - 1x D.5x3 - 3x2 - 5x + 3
Weegy: D. Please rate the answer. (More)
Question
Expert Answered
Updated 223 days ago|1/9/2018 4:58:38 AM
1 Answer/Comment
(5x^2 + 2x - 3)(x - 1)
= 5x^3 + 2x^2 - 3x - 5x^2 - 2x + 3
= 5x^3 - 3x^2 - 5x + 3
Added 223 days ago|1/9/2018 4:58:38 AM
This answer has been confirmed as correct and helpful.
(5x2 + 2x - 3)(x - 1)
Weegy: B.x = 11/10 User: Choose the product. (5x2 + 2x - 3)(x - 1) (More)
Question
Not Answered
Updated 3/8/2014 4:57:34 AM
1 Answer/Comment
(5x2 + 2x - 3)(x - 1)

= 5x^3 - 3x^2 - 5x + 3
Added 3/8/2014 4:57:32 AM
This answer has been confirmed as correct and helpful.
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