Question and answer
The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4)² + y² = 2v3 (x - 4)² + y² = 12 (x + 4)² + y² = 12
Question
Asked 8/31/2012 6:21:09 AM
Updated 7/11/2014 9:38:38 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/11/2014 9:38:30 AM]
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User: The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4)² + y² = 2v3 (x - 4)² + y² = 12 (x + 4)² + y² = 12

Weegy: I am afraid that I cannot see the line referred to. Is it horizontal or vertical, and where does it cross the x or y axis?
rugmaker|Points 2157|

User: The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is a. (x - 4)² + y² = 2v3 b. (x - 4)² + y² = 12 c.(x + 4)² + y² = 12

Question
Asked 8/31/2012 6:21:09 AM
Updated 7/11/2014 9:38:38 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/11/2014 9:38:30 AM]
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The equation of a circle whose center is at (4, 0) and radius is length 2v(3) is (x - 4)² + y² = 12
Added 7/11/2014 9:38:38 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/11/2014 9:41:33 AM]
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Questions asked by the same visitor
The equation of the circle whose center is (0, 3) and radius is length 4 is a.x² + (y- 3)² = 8 b.x² + (y- 3)² = 16 c.x² + (y+ 3)² = 16
Question
Not Answered
Updated 7/11/2014 9:39:14 AM
1 Answer/Comment
The equation of the circle whose center is (0, 3) and radius is length 4 is x² + (y- 3)² = 16
Added 7/11/2014 9:39:14 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/11/2014 9:41:59 AM]
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