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A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e. the altitude of the figure?
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Asked 10/21/2011 4:35:15 PM
Updated 12/1/2014 9:57:23 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [12/1/2014 9:55:07 PM]
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User: A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e. the altitude of the figure?

Weegy: D. 85 square units
Expert answered|Dappordanny|Points 222|

Question
Asked 10/21/2011 4:35:15 PM
Updated 12/1/2014 9:57:23 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [12/1/2014 9:55:07 PM]
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trapezoid area = 1/2 x (a + b) x h = 1/2 x 180 x h = 8100
h = 8100/90 = 90 feet.
the altitude of the lot is 90 feet.
Added 12/1/2014 9:57:23 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [12/2/2014 2:50:17 AM]
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Questions asked by the same visitor
A tool box is a rectangular solid with sides of 19 in., 12 in., and 9 in. What is its volume?
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Expert Answered
Updated 6/24/2014 6:32:52 PM
1 Answer/Comment
A tool box is a rectangular solid with sides of 19 in., 12 in., and 9 in. Its volume is 2,052 in.^3. V = 19*12*9 = 2052
Added 6/24/2014 6:32:52 PM
This answer has been confirmed as correct and helpful.
Confirmed by debnjerry [4/9/2015 2:53:01 PM]
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