Solve by the substitution method 8x + 7y = 19 , -5x + y = 15
Question
Updated 10/25/2014 4:09:51 PM
Edited by andrewpallarca [10/25/2014 4:09:48 PM], Confirmed by andrewpallarca [10/25/2014 4:09:51 PM]
Original conversation
User: Solve by the substitution method 2x + 3y = 11, -8x + y = 47

User: Solve by the substitution method 8x + 7y = 19 , -5x + y = 15

Weegy: -5x + y = 15 y = 15 + 5x substitute it to: 8x + 7(15+5x) = 19 8x + 105 + 35 x = 19 43x = -86 x = -2 solve for y: y = 15 + 5x y = 15 + 5(-2) y = 5

Question
Updated 10/25/2014 4:09:51 PM
Edited by andrewpallarca [10/25/2014 4:09:48 PM], Confirmed by andrewpallarca [10/25/2014 4:09:51 PM]
Rating
3
The solution for 2x + 3y = 11, -8x + y = 47 is:
x = -5, y = 7
SUBSTITUTION METHOD:
2x + 3y = 11, -8 + y = 47;
Isolate y in eq 2:
y = 8x + 47;
Put the value of y to eq. 1, and solve for x:
2x + 3(8x + 47) = 11;
2x + 24x + 141 = 11;
26x + 141 = 11;
26x = 11 - 141;
26x = -130;
x = -130/26;
x = -5;
Put x = -5 to any equation, and solve for y:
2(-5) + 3y = 11;
-10 + 3y = 11;
3y = 11 + 10;
3y = 21;
y = 21/3;
y = 7

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