An investor splits $50,000 into two funds earning 8% and 11%. If total annual return is $4,700, how much was invested in each?

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x + y = 50,000 0.08x + 0.11y = 4,700 Solve: y = 50,000 - x 0.08x + 0.11(50,000 - x) = 4,700 x = 26,667, y = 23,333

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Asked 12 days ago|2/23/2026 12:31:45 PM

Updated 12 days ago|2/23/2026 12:48:22 PM

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cruz30

x + y = 50,000
0.08x + 0.11y = 4,700
Solve: y = 50,000 - x
0.08x + 0.11(50,000 - x) = 4,700
x = 26,667, y = 23,333

Added 12 days ago|2/23/2026 12:47:57 PM

This answer has been confirmed as correct and helpful.

Salas1987

x = -800 / -0.03
x = 26666.67 (approximately)
Now substitute the value of x back into the equation y = 50000 - x to find y:
y = 50000 - 26666.67
y = 23333.33 (approximately)
So, approximately $26,666.67 was invested in the fund earning 8%, and approximately $23,333.33 was invested in the fund earning 11%.

Added 12 days ago|2/23/2026 12:48:22 PM

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