In the myth of "Pandora," what is Hermes advice to Pandora?
A.
To always love her husband
B.
To act nicely toward others
C.
To never open the gift he provided to her
D.
To never tell secrets

s

In the myth of "Pandora," Hermes advice to Pandora was C. To never open the gift he provided to her.

Question

Asked 1/21/2014 11:12:55 AM

Updated 2/1/2014 3:59:36 PM

1 Answer/Comment

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In the myth of "Pandora," Hermes advice to Pandora was C. To never open the gift he provided to her.

Added 2/1/2014 3:59:36 PM

This answer has been confirmed as correct and helpful.

Factor f2 – 12f + 36.
A.
(f – 36)(f + 1)
B.
(f + 6)2
C.
(f – 6)2
D.
(f – 6)(f + 6)
**Weegy:** f^2 – 12f + 36 the factors are: C. (f – 6)^2 **User:** Factor 4y2 – 3y – 1.
A.
(2y + 1)(2y – 1)
B.
(4y + 1)(y – 1)
C.
(4y – 1)(y+ 1)
D.
(y - 4)(4y - 4)
**Weegy:** 4y^2 – 3y – 1 the factors are: B. (4y + 1)(y – 1) (More)

Question

Expert Answered

Asked 1/14/2014 12:36:30 PM

0 Answers/Comments

Factor x2 + 5x + 6.
A.
(x + 3)(x + 2)
B.
(x - 3)(x - 2)
C.
(x - 3)(x + 2)
D.
(x + 3)(x - 2)

Question

Not Answered

Updated 7/9/2014 4:40:08 PM

1 Answer/Comment

x^2 + 5x + 6 = (x + 3)(x + 2)

Added 7/9/2014 4:40:05 PM

This answer has been confirmed as correct and helpful.

Factor pq + 4q – 2p – 8.
A.
(p + 4)(q – 2)
B.
(p – 4)(q + 2)
C.
(p – 4)(q – 2)
D.
(p + 4)(q + 2)
**Weegy:** A. (p + 4)(q – 2) B. (p – 4) is the factor of pq + 4q – 2p – 8. **User:** Factor xy – 6 + 2y – 3x.
A.
(x – 2)(y – 3)
B.
x(y – 3) + 2(y – 3)
C.
(xy – 3x) + (2y – 6)
D.
(x + 2)(y – 3)
**Weegy:** D. (x + 2)(y – 3)
is the factor of xy – 6 + 2y – 3x. (More)

Question

Expert Answered

Asked 1/14/2014 1:00:41 PM

0 Answers/Comments

Simplify (3 + 3i) – (7 + 6i).
A.
–4 – 3i
B.
4 – 3i
C.
4 + 3i
D.
–4 + 9i
**Weegy:** (3 + 3i) – (7 + 6i) is A. –4 – 3i
(More)

Question

Expert Answered

Updated 1/14/2014 1:45:23 PM

0 Answers/Comments

Rewrite y = x2 + 4x + 5 in vertex form.

Question

Updated 12/19/2014 6:34:10 AM

1 Answer/Comment

y = x^2 + 4x + 5 in vertex form is y = (x + 2)^2 + 1.

y = x^2 + 4x + 5

y = (x + 2)^2 - 4 + 5

y = (x + 2)^2 + 1

y = x^2 + 4x + 5

y = (x + 2)^2 - 4 + 5

y = (x + 2)^2 + 1

Added 12/19/2014 6:34:10 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [12/19/2014 6:54:49 AM]

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