Input in standard form the equation of the given line.
The line with m = -1 /2 and b = 1

Question

Asked 4/8/2014 3:59:48 AM

Updated 4/8/2014 9:13:48 PM

4 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [4/8/2014 9:06:00 PM]

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eturker|Points 3067|

eturker|Points 3067|

Question

Asked 4/8/2014 3:59:48 AM

Updated 4/8/2014 9:13:48 PM

4 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [4/8/2014 9:06:00 PM]

Rating

3

The equation of the line through (0, -3) and (3, 0) in standard form is x - y = 3.

Added 4/8/2014 9:09:00 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/8/2014 9:28:59 PM]

3

The equation of the line with m = -1 /2 and b = 1 in standard form is x + 2y = 2.

Added 4/8/2014 9:11:13 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/8/2014 9:29:00 PM]

3

The line that passes through (1, 1) and (3, 4) in standard form is 3x - 2y = 1

Added 4/8/2014 9:13:48 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/8/2014 9:29:05 PM]

Solve the system by the elimination method. Check your work.
2a + 3b = 6
5a + 2b - 4 = 0 **Weegy:** 3-3 = 0 (More)

Question

Updated 5/19/2015 6:50:05 AM

1 Answer/Comment

The solution for 2a + 3b = 6 5a + 2b - 4 = 0 is a = 0 , b = 2.

equation 1 : 2a*5 + 3b*5 = 5*6 ,10a + 15b = 30

equation 2:5a*2 + 2b*2 - 4*2 = 0 , 10a + 4b - 8 = 0

equation 1 minus equation 2

10a + 15b - 10a - 4b + 8 = 30

11b = 22

b = 2

2a + 3*2 = 6

2a = 0

a = 0

equation 1 : 2a*5 + 3b*5 = 5*6 ,10a + 15b = 30

equation 2:5a*2 + 2b*2 - 4*2 = 0 , 10a + 4b - 8 = 0

equation 1 minus equation 2

10a + 15b - 10a - 4b + 8 = 30

11b = 22

b = 2

2a + 3*2 = 6

2a = 0

a = 0

Added 5/19/2015 6:50:05 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [5/19/2015 4:31:07 PM]

Input the equation of the given line in slope-intercept form.
The line with m = 2 and b = -4.
User: Input the equation of the given line in standard form.
The line through (1, -4) and parallel to 2x +3y = 4. **Weegy:** the line with m=2 @ x=3 y-y1=2(x-3) you need to find y1. because 2 line intersecting @ x=3 , y coordinate is the same as well. [ let's find it: y=2/3 *3 -2=0 so point of intersection is: (3,0) the equation of the desired line will be: y-0=2(x-3) y=2x-6 ] (More)

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Not Answered

Updated 4/8/2014 8:31:31 AM

1 Answer/Comment

The line through (1, -4) and parallel to 2x +3y = 4 in standard form is 2x + 3y = -10

Added 4/8/2014 8:31:31 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [4/8/2014 8:32:02 AM]

Input in standard form the equation of the given line.
The line that passes through (1, 1) and (3, 4)
User: Input the equation of the given line in standard form.
The line with m = 2/3 and passing through (1, 1)

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Not Answered

Updated 4/8/2014 8:26:32 AM

1 Answer/Comment

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