Input in standard form the equation of the given line. The line with m = -1 /2 and b = 1
Question
Updated 4/8/2014 9:13:48 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [4/8/2014 9:06:00 PM]
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Original conversation
User: Input in standard form the equation of the given line. The line through (0, -3) and (3, 0)

User: Input in standard form the equation of the given line. The line with m = -1 /2 and b = 1

Weegy: 1/2 x + y = 1. y = -1/2 x + 1. 1/2 x + y = 1. This is one of the standard forms for the given line.
eturker|Points 3067|

User: Input in standard form the equation of the given line. The line with m = -1 /2 and b = 1

Weegy: 1/2 x + y = 1. y = -1/2 x + 1. 1/2 x + y = 1. This is one of the standard forms for the given line.
eturker|Points 3067|

User: Input in standard form the equation of the given line. The line that passes through (1, 1) and (3, 4)

Question
Updated 4/8/2014 9:13:48 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [4/8/2014 9:06:00 PM]
Rating
3
The equation of the line through (0, -3) and (3, 0) in standard form is x - y = 3.

Confirmed by jeifunk [4/8/2014 9:28:59 PM]
3
The equation of the line with m = -1 /2 and b = 1 in standard form is x + 2y = 2.
Confirmed by jeifunk [4/8/2014 9:29:00 PM]
3
The line that passes through (1, 1) and (3, 4) in standard form is 3x - 2y = 1

Confirmed by jeifunk [4/8/2014 9:29:05 PM]

Questions asked by the same visitor
Solve the system by the elimination method. Check your work. 2a + 3b = 6 5a + 2b - 4 = 0
Weegy: 3-3 = 0 (More)
Question
Updated 5/19/2015 6:50:05 AM
The solution for 2a + 3b = 6 5a + 2b - 4 = 0 is a = 0 , b = 2.
equation 1 : 2a*5 + 3b*5 = 5*6 ,10a + 15b = 30
equation 2:5a*2 + 2b*2 - 4*2 = 0 , 10a + 4b - 8 = 0
equation 1 minus equation 2
10a + 15b - 10a - 4b + 8 = 30
11b = 22
b = 2
2a + 3*2 = 6
2a = 0
a = 0
Confirmed by Andrew. [5/19/2015 4:31:07 PM]
Input the equation of the given line in slope-intercept form. The line with m = 2 and b = -4. User: Input the equation of the given line in standard form. The line through (1, -4) and parallel to 2x +3y = 4.
Weegy: the line with m=2 @ x=3 y-y1=2(x-3) you need to find y1. because 2 line intersecting @ x=3 , y coordinate is the same as well. [ let's find it: y=2/3 *3 -2=0 so point of intersection is: (3,0) the equation of the desired line will be: y-0=2(x-3) y=2x-6 ] (More)
Question
Updated 4/8/2014 8:31:31 AM
The line through (1, -4) and parallel to 2x +3y = 4 in standard form is 2x + 3y = -10

Confirmed by andrewpallarca [4/8/2014 8:32:02 AM]
Input in standard form the equation of the given line. The line that passes through (1, 1) and (3, 4) User: Input the equation of the given line in standard form. The line with m = 2/3 and passing through (1, 1)
Question
Updated 4/8/2014 8:26:32 AM
The equation of the line with m = 2/3 and passing through (1, 1) is 2x - 3y = -1.

Confirmed by jeifunk [4/8/2014 8:28:46 AM]
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