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If Anne is 33 years younger than her mother and if the sum of their ages is 75, how old is Anne
Let x be the age of Anne's mother. x - 33 is Anne's age. x + (x - 33) = 75 2x - 33 = 75 2x = 75 + 33 2x = 108 x = 108/2 x = 54 x - 33 = 54 - 33 = 21 Anne is 21 years old.
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Asked 4/30/2015 11:32:06 AM
Updated 4/30/2015 11:57:45 AM
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Let x be the age of Anne's mother.
x - 33 is Anne's age.
x + (x - 33) = 75
2x - 33 = 75
2x = 75 + 33
2x = 108
x = 108/2
x = 54
x - 33 =
54 - 33 =
21
Anne is 21 years old.
Added 4/30/2015 11:57:45 AM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [5/1/2015 1:39:28 PM], Rated good by sujaysen
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(-3.9) + (6.01) - (-7.423)
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Updated 4/30/2015 6:54:09 PM
3 Answers/Comments
The algebraic expression for "fourteen diminished by nine times a number" is: 14 - 9x.
Added 4/30/2015 6:47:20 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [5/1/2015 1:36:30 PM]
(-3.9) + (6.01) - (-7.423)
= -3.9 + 6.01 + 7.423
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This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [5/1/2015 1:37:01 PM]
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Added 4/30/2015 6:53:16 PM
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Updated 4/30/2015 6:46:18 PM
1 Answer/Comment
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Updated 5/3/2015 9:42:44 AM
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Added 5/3/2015 9:42:01 AM
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Confirmed by Andrew. [5/4/2015 9:46:31 AM]
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