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A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m2, how much pressure does the block exert on the tabletop? A. 226.5 Pa B. 367.5 Pa C. 122.5 Pa D. 73.5 Pa
A 7.5 kg block is placed on a table. If it's bottom surface area is 0.6m2, the block exert 122.5 Pa on the tabletop. Solution: P = F/A where F = mg; F = 7.5 ( 9.81) = 73.6 N; P = 73.6 N / 0.6 m^2 = 122.5 Pa.
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Asked 6/17/2019 8:04:33 AM
Updated 28 days ago|7/8/2021 10:57:59 PM
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A 7.5 kg block is placed on a table. If it's bottom surface area is 0.6m2, the block exert 122.5 Pa on the tabletop.

Solution: P = F/A where F = mg; F = 7.5 ( 9.81) = 73.6 N; P = 73.6 N / 0.6 m^2 = 122.5 Pa.
Added 28 days ago|7/8/2021 10:57:59 PM
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