Solve F(x) for the given domain. F(x) = x 2 + 3x - 2 F(-1) =
Question
Asked 3/6/2014 11:05:03 AM
Updated 8/19/2014 11:55:12 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [8/19/2014 11:53:16 PM]
Original conversation
User: Solve F(x) for the given domain. F(x) = x 2 + 3x - 2 F(-1) =

Weegy: (3x-2) squared is 9x^2 - 12x + 4.
twistedechoes|Points 46|

User: Solve F(x) for the given domain. F(x) = x 2 + 3x - 2 F(-1) =

Question
Asked 3/6/2014 11:05:03 AM
Updated 8/19/2014 11:55:12 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [8/19/2014 11:53:16 PM]
Rating
3
F(x) = x^2 + 3x - 2
F(-1) = (-1)^2 + 3(-1) - 2 = 1 - 3 - 2 = -4
Added 8/19/2014 11:55:12 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/19/2014 11:55:39 PM]

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Questions asked by the same visitor
Solve G(x) for the given domain. G(x) = 3x 2 - 2x - 1 G(a + b) =
Weegy: x = 27/4 User: Solve F(x) for the given domain. F(x) = x 2+ 3x - 2 F(a) = Weegy: x = 27/4 (More)
Question
Updated 8/19/2014 11:52:20 PM
G(x) = 3x^2 - 2x - 1
G(a + b) = 3(a + b)^2 - 2(a + b) - 1
= 3a^2 + 6ab + 3b^2 - 2a - 2b - 1

Added 8/19/2014 11:52:20 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/19/2014 11:54:21 PM]
Solve F(x) for the given domain. F(x) = x 2+ 3x - 2 F(a) =
Question
Updated 8/19/2014 11:50:50 PM
F(x) = x^2+ 3x - 2
F(a) = a^2 + 3a - 2
Added 8/19/2014 11:50:50 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/19/2014 11:51:34 PM]
Solve G(x) for the given domain. G(x) = 3x 2 - 2x - 1 G(6) =
Question
Updated 8/19/2014 11:50:03 PM
G(x) = 3x^2 - 2x - 1
G(6) = 3(6^2) - 2(6) - 1 = 108 - 12 - 1 = 95
Added 8/19/2014 11:50:03 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/19/2014 11:51:48 PM]
Solve F(x) for the given domain. F(x) = x 2 + 3x - 2 F(1) =
Weegy: 3x - 5 = 16; 3x = 21; x = 7. (More)
Question
Updated 8/19/2014 11:53:05 PM
F(x) = x^2 + 3x - 2
F(1) = 1^2 + 3(1) - 2 = 1 + 3 - 2 = 2

Added 8/19/2014 11:53:05 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/19/2014 11:54:00 PM]
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