Simplify the expression (x^3y-2z^4)^3
(x^3y - 2z^4)^3 = (x^3y - 2z^4)(x^3y - 2z^4)(x^3y - 2z^4) = (x^6y^2 - 4x^3yz^4 + 4z^16)(x^3y - 2z^4) = x^9y^3 - 4x^6y^2z^4 - 2x^6y^2z^4 + 4x^3yz^8 + 8x^3yz^8 - 8z^12 = x^9y^3 - 6x^6y^2z^4 + 12x^3yz^8 - 8z^12
Question
Updated 10/29/2014 7:25:07 AM
Edited by andrewpallarca [10/29/2014 7:25:07 AM]
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(x^3y - 2z^4)^3
= (x^3y - 2z^4)(x^3y - 2z^4)(x^3y - 2z^4)
= (x^6y^2 - 4x^3yz^4 + 4z^16)(x^3y - 2z^4)
= x^9y^3 - 4x^6y^2z^4 - 2x^6y^2z^4 + 4x^3yz^8 + 8x^3yz^8 - 8z^12
= x^9y^3 - 6x^6y^2z^4 + 12x^3yz^8 - 8z^12
5
(x^3y - 2z^4)^3
= (x^3y - 2z^4)(x^3y - 2z^4)(x^3y - 2z^4)
= (x^6y^2 - 4x^3yz^4 + 4z^16)(x^3y - 2z^4)
= x^9y^3 - 4x^6y^2z^4 + 4x^3yz^16 - 2x^6y^2z^4 + 8x^3yz^8 - 8z^20
= x^9y^3 - 6x^6y^2z^4 + 4x^3yz^16 +8x^3yz^8 - 8z^20
This answer has been flagged as incorrect.
Flagged by andrewpallarca [10/29/2014 7:25:13 AM]

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