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Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8. A. b = 5, 2, 2, and 4 B. b = 2 and 4 C. b = 5 and 2 D. b = 2 and 4
The illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8 are b = -2 and 4. Solution: b^2-2b-8=0; (b-4)(b+2)=0; b = 4 and -2.
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Question|Asked by baichu
Asked 2/26/2019 1:28:52 PM
Updated 126 days ago|7/29/2020 12:39:34 PM
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The illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8 are b = -2 and 4. Solution: b^2-2b-8=0; (b-4)(b+2)=0; b = 4 and -2.
Added 126 days ago|7/29/2020 12:39:34 PM
This answer has been confirmed as correct and helpful.
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The GCF of 14x2 and 4xy is 2x.

Added 7/13/2019 3:51:34 PM
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16. Factor -25x - 5. A. -5(5x^2 2) B. -5(5x 1) C. -5x(25x 5) D. -5(5x^2 1)
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Added 47 days ago|10/15/2020 10:03:23 PM
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16. Factor –25x – 5. A. –5(5x2 + 2) B. –5(5x + 1) C. –5x(25x + 5) D. –5(5x2 + 1)
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Updated 7/13/2019 3:50:51 PM
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–25x – 5 = –5(5x + 1)
Added 7/13/2019 3:50:51 PM
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Question|Asked by baichu
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Updated 5/25/2019 2:20:35 AM
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The hypotenuse of a right triangle is 6 inches and one of the legs is 6 inches, the exact value of the other leg is 30 inches.
Added 5/25/2019 2:20:35 AM
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