The length of a rectangle is 4 ft less than three times the width, and the area of the rectangle is 55 ft^2 . Find the dimensions of the rectangle.
Let w be the width of this rectangle then its length is 3w - 4. Its area = w(3w - 4) = 55; 3w^2 - 4w - 55 = 0; (w - 5)(3 + 11) = 0; so w = 5 feet. And the length is 3(5) - 4 = 15 - 4 = 11 feet. The length of this rectangle is 11 feet and the [ width is 5 feet. ]
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Asked 4/17/2014 8:31:22 PM
Updated 4/17/2014 11:07:48 PM
This answer has been confirmed as correct and helpful.
Confirmed by debnjerry [4/17/2014 11:07:48 PM]
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The area of a rectangle is 45 ft^2 , and the length of the rectangle is 1 ft more than double the width. Find the dimensions of the rectangle
Question
Updated 5/19/2014 12:38:25 AM
Let w be the width of the rectange, its length is: 2w + 1.
The area of a rectangle is 45 ft^2, then w(2w + 1) = 45
2w^2 + w - 45 = 0
(w + 5)(2w - 9) = 0
w = -5 (not possible) or w = 9/2 ft.
Length = 2(9/2) + 1 = 10 ft.
Added 5/19/2014 12:38:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/19/2014 12:39:04 AM]
The area of a rectangle is 99 m^2 , and the length of the rectangle is 7 m more than double the width. Find the dimensions of the rectangle
Weegy: SOLUTION: The width of a rectangle is 7m more than the length. Find the dimensions if the ... x^2 + 7x - 60 = 0 {subtracted 60 from both sides} (x + 12)(x - 5) = 0 ... › Customizable Word Problem Solvers › Geometry (More)
Question
Updated 5/19/2014 12:35:20 AM
Let w be the width of the rectange, its length is: 2w + 7.
The area of a rectangle is 99 m^2, that is: w(2w + 7) = 99
2w^2 + 7w - 99 = 0
(w + 9)(2w - 11) = 0
w = -9 (impossible) or w = 11/2 m
Length = 2(11/2) + 7 = 18 m.
Added 5/19/2014 12:35:20 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/19/2014 12:39:08 AM]
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