What is the vertex form of the expression of y = 6x2 - 36x + 58
The vertex form of the expression of y = 6x^2 - 36x + 58 is (3, 4)
Question
Updated 4/23/2014 8:52:36 PM
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3
The vertex form of the expression of y = 6x^2 - 36x + 58 is (3, 4)
Confirmed by jeifunk [4/23/2014 8:53:48 PM]

Questions asked by the same visitor
. Which of the following is the vertex form of the expression below? y = 6x2 - 36x + 58 A. y = 6(x - 3)2 + 4 B. y = 6(x - 3)2 + 112 C. y = 6(x - 3)2 + 58 D. y = 6(x + 3)2 + 4
Question
Updated 4/23/2014 8:55:12 PM
The following that is the vertex form of the expression y = 6x^2 - 36x + 58 is: A. y = 6(x - 3)^2 + 4.
y = 6x^2 - 36x + 58
y = 6x^2 - 36x + 54 + 4
y = 6(x^2 - 6x + 9) + 4
y = 6(x - 3)^2 + 4
Confirmed by jeifunk [4/23/2014 8:56:03 PM]
Solve for x in the following equation. x2 - 10x + 16 = 0
Weegy: x2 - x - 90 = 0 in factored form is (x-10)(x+9)=0 User: Solve for x in the following equation. x2 - 10x + 16 = 0 A. x = -2; -8 B. x = 1; 16 C. x = 2; 8 D. x = 5; 5 (More)
Question
Updated 4/18/2014 9:05:30 AM
x^2 - 10x + 16 = 0
(x - 2)(x - 8) = 0
x = 2 or x = 8
Confirmed by yumdrea [4/18/2014 9:09:25 AM]
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