Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 5x + 7 = 0 double root real and rational roots real and irrational roots non-real roots
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Updated 11/18/2014 8:16:51 AM
Followed by kirachey, Unfollowed by kirachey
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User: Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 5x + 7 = 0 double root real and rational roots real and irrational roots non-real roots

Weegy: x^2 - 5x + 7 = 0
discriminant = b^2 - 4ac = (-5)^2 - 4(1)(7) = 25 - 28 = -3 < 0
There are two imaginary roots for the equation x^2 - 5x + 7 = 0

User: Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 4x + 4 = 0 double root real and rational roots real and irrational roots non-real roots

Question
Updated 11/18/2014 8:16:51 AM
Followed by kirachey, Unfollowed by kirachey
Rating
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x^2 - 4x + 4 = 0
discriminant = b^2 - 4ac = (-4)^2 - 4(1)(4) = 16 - 16 = 0
there is double root (one repeated root) for the equation x^2 - 4x + 4 = 0.
Confirmed by jeifunk [11/18/2014 8:25:01 AM]

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Solve x2 + 8x + 8 = 0 by completing the square
Weegy: ( - 8x) ? ( - 2) = 4x User: Use completing the square to solve the equation x2 - 10x = -8. Which equation is used in the process? x2 - 10x + 25 = 17 x2 - 10x + 25 = -8 x2 - 10x - 25 = -33 (More)
Question
Updated 11/10/2014 11:58:08 AM
x^2 + 8x + 8 = 0
x^2 + 8x + 16 = 8
(x + 4)^2 = 8
x + 4 = sqrt 8 or x + 4 = -sqrt 8
x = -4 + 2sqrt 2 or -4 - 2sqrt 2
Confirmed by andrewpallarca [11/11/2014 10:16:51 AM]
Use completing the square to solve the equation x^2 - 10x = -8. the equation used in the process is x^2 - 10x + 25 = 17
Confirmed by andrewpallarca [11/11/2014 10:17:16 AM]
Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite. x + y = 6 x - y = 0 one solution no solution infinite
Weegy: |x - 1| = 3 x - 1 = -3 or x - 1 = 3; x - 1 = 3; x = 3 + 1; x = 4; x - 1 = -3; x = -3 + 1; x = -2; x = {4, -2} User: Use the discriminant to determine the nature of the roots of the following equation. y2 - 5y - 3 = 0 Double root real and rational root real and irrational root non-real root (More)
Question
Updated 11/18/2014 8:09:43 AM
x + y = 6
x - y = 0
adding up equations above the result is:
2x = 6
x = 6/2 = 3
y = x = 3
There is one solution for the system x + y = 6 x - y = 0 which is (3, 3)
Confirmed by sujaysen [11/18/2014 9:32:47 AM]
y^2 - 5y - 3 = 0
a = 1, b = -5, c = -3
discriminant = b^2 - 4ac = (-5)^2 - 4(1)(-3) = 25 + 12 = 37 > 0
there are real and irrational roots for the equation y^2 - 5y - 3 = 0.
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