An arithmetic series consists of consecutive integers that are multiples of 4. What’s the sum of the first nine terms of this sequence if the first term is 0
An arithmetic series consists of consecutive integers that are multiples of 4. 144 is the sum of the first nine terms of this sequence if the first term is 0. Solution: 2 is the nineth term in the series. Sum = 0 + 4 + 8 + 12 + ... 32 = 144. [ a1 = 0 n = 9 d = 4 Formula for the 9th term: a9 = a1 + (n - 1)*d; Substitute and Solve: a9 = 0 + (9 - 1)*4; a9 = 8*4 = 32; Find the sum of the first 9 terms: Sum = (a1 + a9)*n/2 Sum = (0 + 32)*9/2; = 32 * 9/2; = 32 * 4.5; = 144. ]
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Asked 7/25/2022 5:57:33 PM
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