Rewrite y = x2 + 4x + 5 in vertex form.

y = x^2 + 4x + 5 in vertex form is y = (x + 2)^2 + 1. y = x^2 + 4x + 5 y = (x + 2)^2 - 4 + 5 y = (x + 2)^2 + 1

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Asked 1/14/2014 1:27:30 PM

Updated 12/19/2014 6:34:10 AM

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y = x^2 + 4x + 5 in vertex form is y = (x + 2)^2 + 1.

y = x^2 + 4x + 5

y = (x + 2)^2 - 4 + 5

y = (x + 2)^2 + 1

y = x^2 + 4x + 5

y = (x + 2)^2 - 4 + 5

y = (x + 2)^2 + 1

Added 12/19/2014 6:34:10 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [12/19/2014 6:54:49 AM]

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