limit (x²-1)/(x-1) = x+1.

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Asked 37 days ago|6/8/2026 8:50:39 AM

Updated 37 days ago|6/8/2026 9:33:23 AM

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User: limit (x²-1)/(x-1) = x+1.

Weegy: 5/7(x+y)-1/7(x-1)=
5x + 5y/7 - x - 1/7 =
5x - x + 5y - 1/7 =
4x + 5y - 1/7

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Question

Asked 37 days ago|6/8/2026 8:50:39 AM

Updated 37 days ago|6/8/2026 9:33:23 AM

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alfred123

Problem:
→ limit (x² 1) / (x 1)

Step 1: Factor numerator
(x² 1) = (x 1)(x + 1)

Step 2: Simplify fraction
[(x 1)(x + 1)] / (x 1) = x + 1

Step 3: Apply limit as x 1
x + 1 = 1 + 1 = 2

Final Answer: Limit = 2

Added 37 days ago|6/8/2026 9:33:11 AM

This answer has been confirmed as correct and helpful.

cruz30

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Added 37 days ago|6/8/2026 9:33:23 AM

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Deleted by cruz30 [6/8/2026 9:33:27 AM]

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Updated 37 days ago|6/8/2026 9:04:54 AM

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Given: m = 5 kg, a = 3.2 m/s^2
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A projectile is launched at 40 m/s at 30°; calculate horizontal range using R = (v² sin 2 )/g = (40² × sin60°)/9.8.

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Updated 37 days ago|6/8/2026 9:11:35 AM

1 Answer/Comment

cruz30

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Added 37 days ago|6/8/2026 9:11:35 AM

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Calculate mass of NaCl using mass = moles × molar mass = 0.75 × 58.5.

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Question

Updated 37 days ago|6/8/2026 9:29:15 AM

1 Answer/Comment

cruz30

Given: mass = moles × molar mass
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= 43.875
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Added 37 days ago|6/8/2026 9:29:15 AM

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Solve 3x² - 5x + 2 = 0 using quadratic formula x = [-b ± sqrt(b²-4ac)]/2a.

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Question

Updated 37 days ago|6/8/2026 9:28:55 AM

1 Answer/Comment

cruz30

Given: 3x^2 - 5x + 2 = 0
a = 3, b = -5, c = 2
x = [-b ± sqrt(b^2 - 4ac)] / 2a
= [5 ± sqrt((-5)^2 - 4(3)(2))] / 6
= [5 ± sqrt(25 - 24)] / 6
= [5 ± sqrt(1)] / 6
= [5 ± 1] / 6
x = (5 + 1)/6 = 6/6 = 1
x = (5 - 1)/6 = 4/6 = 2/3
Answer = x = 1, 2/3

Added 37 days ago|6/8/2026 9:28:55 AM

This answer has been confirmed as correct and helpful.

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