The system shown has _____ solution(s). y = x + 1 2y - x = 6 no one infinite
Question
Updated 3/30/2014 9:46:19 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [3/30/2014 9:46:19 PM]
Original conversation
User: The system shown has _____ solution(s). y = x + 1 2y - x = 6 no one infinite

Weegy: y=x+12_y-x=2... Replace all occurrences of y with the solution found by solving the last equation for y. [ In this case, the value substituted is x+12. y=x+12_(x+12)-x=2.. Remove the parentheses around the expression x+12. y=x+12_x+12-x=2... Since x and -x are like terms, add -x to x to get 0. y=x+12_0+12=2... Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression. y=x+12_12=2... Since 12 is not equal to 2, there are no solutions. The system shown has no Solutions. ]

Question
Updated 3/30/2014 9:46:19 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [3/30/2014 9:46:19 PM]
Rating
3
y = x + 1, the first equation
2y - x = 6, the second equation
Replace y in the second equation with the first one we get:
2(x + 1) - x = 6
solve the equation we get x = 4
so, y = 4 + 1 = 5
The system y = x +1, 2y - x = 6 has one solution (4, 5)
Confirmed by jeifunk [3/30/2014 9:52:50 PM]

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