One jar holds 16 red marbles and 4 blue marbles. A second jar holds 75 white marbles and 25 blue marbles. What is the probability that a blue marble will be drawn from both jars?

Question

Asked 2/12/2015 1:18:51 PM

Updated 2/12/2015 10:20:51 PM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by janezeshun [2/12/2015 10:18:57 PM]

lena.G|Points 261|

x+1=2

x = 2 - 1

x = 1

x+1=2

x = 2 - 1

x = 1

elionor|Points 143|

Andrew.|Points 48760|

businesslady|Points 1133|

Question

Asked 2/12/2015 1:18:51 PM

Updated 2/12/2015 10:20:51 PM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by janezeshun [2/12/2015 10:18:57 PM]

Rating

3

The conic section for the equation 4x^2 - 25y^2 = 100 is Hyperbola.

Added 2/12/2015 10:18:41 PM

3

The distance between the points. (2, 3) and (-3, -6) is 106^1/2 .

distance^2 = (2 + 3)^2 + (3 + 6)^2

= 25 + 81

= 106

distance = 106^1/2

distance^2 = (2 + 3)^2 + (3 + 6)^2

= 25 + 81

= 106

distance = 106^1/2

Added 2/12/2015 10:20:51 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/13/2015 6:56:00 AM]

Find the roots.
2x 2 + 4x - 5 =0 User: Choose the correct conic section to match the equation.
y 2 = 36x **Weegy:** The conic section for the equation y^2 = 36x is Parabola. **User:** Choose the best description of the roots of the equation 3x 2 - 4x + 5 = 0.
**User:** Simplify the expression.
(-4 + 7i)(-4 - 7i) (More)

Question

Updated 2/12/2015 7:58:07 PM

3 Answers/Comments

(-4 + 7i)(-4 - 7i) = (-4)^2 - (7i)^2 = 16 - 49i^2

if i^2 = -1, 16 - 49i^2 = 16 - 49(-1) = 16 + 49 = 65

if i^2 = -1, 16 - 49i^2 = 16 - 49(-1) = 16 + 49 = 65

Added 2/12/2015 7:44:48 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/13/2015 6:52:35 AM]

3x^2 - 4x + 5 = 0

a = 3, b = -4, c = 5

b^2 - 4ac = (-4)^2 - 4(3)(5) = 16 - 60 = -44 < 0

there are two complex roots for the equation 3x^2 - 4x + 5 = 0.

a = 3, b = -4, c = 5

b^2 - 4ac = (-4)^2 - 4(3)(5) = 16 - 60 = -44 < 0

there are two complex roots for the equation 3x^2 - 4x + 5 = 0.

Added 2/12/2015 7:52:37 PM

2x^2 + 4x - 5 =0

a = 2, b = 4, c = -5

b^2 - 4ac = 4^2 - 4(2)(-5) = 16 + 40 = 56 > 0

there are two real roots for the equations and the roots are:

x = (-4 ± sqrt 56)/4

= (-4 ± 2 sqrt 14)/4

= (-2 ± sqrt 14)/2

a = 2, b = 4, c = -5

b^2 - 4ac = 4^2 - 4(2)(-5) = 16 + 40 = 56 > 0

there are two real roots for the equations and the roots are:

x = (-4 ± sqrt 56)/4

= (-4 ± 2 sqrt 14)/4

= (-2 ± sqrt 14)/2

Added 2/12/2015 7:58:07 PM

Solve for x.
8x + 2 - 5 = 11 User: Find the equation for a hyperbola centered at (0, 0), with foci at (-, 0) and (, 0) and vertices at (3, 0) and (-3, 0).

Question

Updated 2/12/2015 3:48:36 PM

1 Answer/Comment

8x + 2 - 5 = 11;

8x - 3 = 11;

8x = 11 + 3;

8x = 14;

x = 14/8;

x = 7/4

8x - 3 = 11;

8x = 11 + 3;

8x = 14;

x = 14/8;

x = 7/4

Added 2/12/2015 3:48:36 PM

This answer has been confirmed as correct and helpful.

Find the simplest form of the general term for the sequence 11, 15, 19, 23, . . .
**Weegy:** The simplest form of the general term for the sequence 11, 15, 19, 23, . . .
is: 4n-1. **User:** Find the equation of a circle that has its center at (-4, 3) and has a radius of 5.
**User:** Twelve children play musical chairs. If there are three chairs, how many ways are there for three children to sit?
**Weegy:** The answer is 36 ways. **User:** Twelve children play musical chairs. If there are three chairs, how many ways are there for three children to sit?
220
1,320
660 (More)

Question

Updated 2/13/2015 12:09:25 AM

2 Answers/Comments

The simplest form of the general term for the sequence 11, 15, 19, 23, . . . is 4n + 7 .

common difference = 23 - 19 = 4

An = 11 + (n - 1)*4

An = 11 + 4n - 4

An = 4n + 7

common difference = 23 - 19 = 4

An = 11 + (n - 1)*4

An = 11 + 4n - 4

An = 4n + 7

Added 2/13/2015 12:00:26 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/13/2015 6:58:32 AM]

Twelve children play musical chairs. If there are three chairs, there are 1320 ways for three children to sit.

12*11*10 =1320

12*11*10 =1320

Added 2/13/2015 12:09:25 AM

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