Given |2x - 3| = 2, find the solutions to the equation. a. .5 and 2.5 c. 2.3 and 4.1 b. 1 and 3 d. 0 and 2

Question

Asked 11/19/2014 2:25:10 PM

Updated 11/20/2014 1:24:55 AM

1 Answer/Comment

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Flagged by janezeshun [11/20/2014 1:22:56 AM]

s

Multiply 2 on both sides:

x^2 - 2x + 10 = 0, with coefficient a = 1, b = -2, c = 10

b^2 - 4ac = (-2)^2 - 4(1)(10) = 4 - 40 = - 36 < 0 (there are two complex solutions)

x = [2 +/- sqrt (-36)/]/2 = 1 +/- 3i

The two solutions are 1 + 3i, 1 - 3i

Question

Asked 11/19/2014 2:25:10 PM

Updated 11/20/2014 1:24:55 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by janezeshun [11/20/2014 1:22:56 AM]

Rating

5

Given |2x - 3| = 2, find the solutions to the equation are 0.5 and 2.5 .

when 2x - 3 > 0 , x > 3/2

2x - 3 = 2

x = 5/2

x = 2.5

when 2x - 3 < 0 , x < 3/2

-2x + 3 = 2

-2x = -1

x = 1/2

x = 0.5

when 2x - 3 > 0 , x > 3/2

2x - 3 = 2

x = 5/2

x = 2.5

when 2x - 3 < 0 , x < 3/2

-2x + 3 = 2

-2x = -1

x = 1/2

x = 0.5

Added 11/20/2014 1:24:55 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/20/2014 1:43:04 AM]

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