Given |2x - 3| = 2, find the solutions to the equation. a. .5 and 2.5 c. 2.3 and 4.1 b. 1 and 3 d. 0 and 2
Question
Updated 11/20/2014 1:24:55 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/20/2014 1:22:56 AM]
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Original conversation
User: Given |2x - 3| = 2, find the solutions to the equation. a. .5 and 2.5 c. 2.3 and 4.1 b. 1 and 3 d. 0 and 2

Weegy: 1/2x^2 - x + 5 = 0
Multiply 2 on both sides:
x^2 - 2x + 10 = 0, with coefficient a = 1, b = -2, c = 10
b^2 - 4ac = (-2)^2 - 4(1)(10) = 4 - 40 = - 36 < 0 (there are two complex solutions)
x = [2 +/- sqrt (-36)/]/2 = 1 +/- 3i
The two solutions are 1 + 3i, 1 - 3i

Question
Updated 11/20/2014 1:24:55 AM
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/20/2014 1:22:56 AM]
Rating
5
Given |2x - 3| = 2, find the solutions to the equation are 0.5 and 2.5 .
when 2x - 3 > 0 , x > 3/2
2x - 3 = 2
x = 5/2
x = 2.5
when 2x - 3 < 0 , x < 3/2
-2x + 3 = 2
-2x = -1
x = 1/2
x = 0.5
Confirmed by jeifunk [11/20/2014 1:43:04 AM]

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