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Find the product of m^2 (m^3)^4
m^2 * (m^3)^4 = m^2 * m^12; = m^14
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Asked 1/20/2016 11:22:18 AM
Updated 1/20/2016 11:38:23 AM
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m^2 * (m^3)^4

= m^2 * m^12;

= m^14
Added 1/20/2016 11:38:23 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [1/20/2016 11:42:26 AM]
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Questions asked by the same visitor
11y^3 - (-5y^3)
Weegy: -5y - 9 = y - 1; -5y - y = - 1 + 9; -6y = 8; y = -8/6; y = -4/3 User: 11y^3 - (-5y^3) Weegy: -5y - 9 = y - 1; -5y - y = - 1 + 9; -6y = 8; y = -8/6; y = -4/3 User: Factor 3a^3 + 7a^5. (More)
Question
Updated 1/20/2016 12:32:19 PM
2 Answers/Comments
11y^3 - (-5y^3) = 16y^3
Added 1/20/2016 12:32:05 PM
This answer has been confirmed as correct and helpful.
3a^3 + 7a^5 = a^3(7a^2 + 3)
Added 1/20/2016 12:32:19 PM
This answer has been confirmed as correct and helpful.
Factor 6a^4 + 18a^3 + 12a^2.
Question
Updated 1/20/2016 11:30:06 AM
1 Answer/Comment
6a^4 + 18a^3 + 12a^2

= 6a^2(a^2 + 3a + 2);

= 6a^2(a + 1)(a + 2)
Added 1/20/2016 11:30:06 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [1/20/2016 11:32:56 AM]
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