What is the equation, in standard form, of the line that passes through (-5,6) and has a slope of 2?
Question
Updated 7/22/2014 11:06:08 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/22/2014 11:06:08 PM]
Original conversation
User: What is the equation, in standard form, of the line that passes through (-5,6) and has a slope of 2?

Weegy: Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept You already know the slope is -2, so the equation so far is y = -2x + b. [ Now solve for b by substituting the point (10, -1) for x and y into the equation respectively: y = -2x + b (substitute 10 for x and -1 for y) -1 = -2(10) + b (multiply) -1 = -20 + b (add 20 to both sides) 19 = b ANSWER: The equation of the line is y = -2x + 19. ]
nrat|Points 62|

User: What is the equation, in slope-intercept form, of the line passing through the points (-a,b) and (b,-a)?

Question
Updated 7/22/2014 11:06:08 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/22/2014 11:06:08 PM]
Rating
3
The equation, in standard form, of the line that passes through (-5, 6) and has a slope of 2 is 2x - y = -16
Confirmed by jeifunk [7/22/2014 11:05:47 PM]
3
The equation, in slope-intercept form, of the line passing through the points (-a,b) and (b,-a) is y = - x - a + b
Confirmed by jeifunk [7/22/2014 11:08:02 PM]

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