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Factor completely, then place the factors in the proper location on the grid. y2x - yx - 20
y^2x - yx - 20; = y*yx - 5yx + 4yx - 5*4; = (y - 5)(yx + 4)
Question|Asked by little.green.dalek
Asked 4/4/2016 5:57:21 PM
Updated 4/5/2016 10:08:13 PM
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y^2x - yx - 20;
= y*yx - 5yx + 4yx - 5*4;
= (y - 5)(yx + 4)
Added 4/5/2016 10:08:13 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/5/2016 10:21:16 PM]
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Questions asked by little.green.dalek
Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending powers of a. (a - 6)(a 2 +6a + 36)
Weegy: 3-3 = 0 (More)
Question|Asked by little.green.dalek
Expert Answered
Updated 3/30/2016 9:45:52 PM
1 Answer/Comment
(a - 6)(a^2 +6a + 36)
=a^3 + 6a^2 + 36a - 6a^2 - 36a - 216
=a^3 - 216
Added 3/30/2016 9:45:51 PM
This answer has been confirmed as correct and helpful.
Factor completely, then place the answer in the proper location on the grid. 49x 2 + 42xy + 9y 2
Question|Asked by little.green.dalek
Not Answered
Updated 3/30/2016 8:57:19 PM
1 Answer/Comment
49x^2 + 42xy + 9y^2;
= 7x*7x + 2*7x*3y + 3y*3y;
= (7x + 3y)(7x + 3y)
Added 3/30/2016 8:57:19 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [3/30/2016 9:43:09 PM]
Place the indicated product in the proper location on the grid. (b2 + 8 )(b2 - 8)
Question|Asked by little.green.dalek
Expert Answered
Updated 4/4/2016 8:59:00 PM
1 Answer/Comment
(b2 + 8 )(b2 - 8)
=b4 - 8b2 + 8b2 - 64
=b4 - 64
Added 4/4/2016 8:58:50 PM
This answer has been confirmed as correct and helpful.
Factor completely, then place the factors in the proper location on the grid. b2 - 7b + 12
Weegy: b^2 - 7b + 12 is = (b - 3)(b - 4) (More)
Question|Asked by little.green.dalek
Expert Answered
Updated 4/4/2016 9:00:18 PM
0 Answers/Comments
Factor completely, then place the factors in the proper location on the grid. a2 - 5a - 6
Weegy: a^2 - 5a - 6 = (a + 1)(a - 6) (More)
Question|Asked by little.green.dalek
Expert Answered
Updated 4/4/2016 9:05:03 PM
0 Answers/Comments
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