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Simplify b(a + b) - a(a - b). a2 + 2ab + b2 a2 - 2ab + b2 -a2 + 2ab + b2 -a2 - 2ab - b2
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Asked 6/25/2015 9:08:59 AM
Updated 6/25/2015 11:42:27 PM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [6/25/2015 11:42:26 PM], Confirmed by Andrew. [6/25/2015 11:42:27 PM]
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User: Simplify b(a + b) - a(a - b). a2 + 2ab + b2 a2 - 2ab + b2 -a2 + 2ab + b2 -a2 - 2ab - b2

Weegy: b(a + b) - a(a - b) = ab + b^2 - a^2 + ab = -a^2 + 2ab + b^2


User: Find the product. -2x(x^2 - 3) -2x3 - 6x -2x3 + 6x -2x2 + 6x 6x3

Weegy: -2x(x^2 - 3) = -2x^3 + 6x
jerry06|Points 33270|

User: Find the product. (6a + b)2 12a2 + ab + b2 36a2 + ab + 36b2 36a2 + 12ab + b2 36a2 + b2

Weegy: (6a + b)^2
= 6a*6a + 2*6a*b + b*b
= 36a^2 + 12ab + b^2


User: Find the product. (-d + 4)(-d - 4) -d2 - 16 d2 - 16 d2 + 16 d2 - 8d - 16

Weegy: (-d + 4)(-d - 4)
= d^2 + 4d - 4d - 16
= d^2 - 16



User: Multiply (6z 2 - 4z + 1)(8 - 3z). 18z3 - 60z2 + 35z - 8 48z2 - 18z + 8 6z2 - 7z + 9 -18z3 + 60z2 - 35z + 8

Question
Asked 6/25/2015 9:08:59 AM
Updated 6/25/2015 11:42:27 PM
1 Answer/Comment
This answer has been confirmed as correct and helpful.
Edited by Andrew. [6/25/2015 11:42:26 PM], Confirmed by Andrew. [6/25/2015 11:42:27 PM]
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(6z^2 - 4z + 1)(8 - 3z)
= 48z^2 - 32z + 8 - 18z^3 + 12z^2 - 3z
= -18z^3 + 60z^2 - 35z + 8
Added 6/25/2015 10:10:01 PM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [6/25/2015 11:45:48 PM]
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Question
Updated 6/26/2015 5:48:13 PM
0 Answers/Comments
Multiply (6z 2 - 4z + 1)(8 - 3z). 18z3 - 60z2 + 35z - 8 48z2 - 18z + 8 6z2 - 7z + 9 -18z3 + 60z2 - 35z + 8
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Question
Not Answered
Updated 6/26/2015 10:02:18 AM
2 Answers/Comments
(y^3 - 125) ÷ (y - 5)
= (y^2 + 5y + 25)*(y - 5)/(y - 5)
= y^2 + 5y + 25
Added 6/26/2015 12:06:06 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/26/2015 10:02:16 AM]
48a^3bc^2 / (3abc)
= 48a^2c/3
= 16a^2c
Added 6/26/2015 10:01:29 AM
This answer has been confirmed as correct and helpful.
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Not Answered
Updated 7/7/2015 1:39:19 AM
1 Answer/Comment
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Added 7/7/2015 12:37:09 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [7/7/2015 1:41:30 AM]
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