What is the slope of the line that passes through the given points? (6, 2) and (7, 4) A. 1/2 B. -2 C. -1/2 D. 2
Question
Updated 4/5/2014 12:01:59 PM
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Flagged by andrewpallarca [4/5/2014 12:01:59 PM]
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User: What is the slope of the line that passes through the given points? (6, 2) and (7, 4) A. 1/2 B. -2 C. -1/2 D. 2

Weegy: The slope of the line that passes through the points (3, ?4) and (?7, 1) is m = [1 - (-4)]/(-7 - 3) = 5/-10 = -1/2

Question
Updated 4/5/2014 12:01:59 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [4/5/2014 12:01:59 PM]
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The slope of the line that passes through (6, 2) and (7, 4) is 2.

m = y2 - y1/x2-x1;

m = (4 - 2)/7 - 6);

m = 2/1;

m = 2

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What is the slope of the line that passes through the given points? (6, 2) and (7, 4) A. 1/2 B. -2 C. -1/2 D. 2
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Question
Updated 4/5/2014 8:38:33 AM
The slope of the line that passes through the points (6, 2) and (7, 4) is 2.

Confirmed by andrewpallarca [4/9/2014 12:50:57 PM]
What is the equation of the line in slope-intercept form? the line perpendicular to y = 1/3x + 5 through (2, 1) A. y = 1/3x + 7 B. y = -1/3x + 7 C. y = -3x + 7 D. y = 3x + 7 User: Tickets to a concert are available online for \$20 each, plus a one-time handling fee of \$1.75. The total cost is a function of the number of tickets bought. What function rule models the cost of the concert tickets ( t )? Evaluate the function for 3 tickets. A. 20t + 1.75; \$61.75 B. 20t + ...
Weegy: The function rule models the cost of the concert tickets is: 20t + 1.75; \$61.75 User: Let g(x) be the reflection of f(x) = x2 +3 in the x-axis. What is the function rule for g(x)? A. g(x) = -x2 - 3 B. g(x) = -x2 + 3 C. g(x) = x2 - 3 D. g(x) = x2 + 3 Weegy: D. g(x) = x2 + 3 User: what is the graph of the absolute value function y = 2 x (More)
Question
Updated 4/1/2014 8:08:07 PM
Let g(x) be the reflection of f(x) = x^2 +3 in the x-axis. The function rule for g(x) is A. g(x) = -x^2 - 3
(y = - f(x) is its reflection about the x-axis, so g(x) = - f(x) = -x^2 - 3)
Confirmed by jeifunk [4/1/2014 8:27:02 PM]
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