A bag has 3 red and 5 blue balls. Draw 3 balls without replacement. Probability exactly 2 are red.

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Total ways = C(8,3) = 56 Favorable = C(3,2) × C(5,1) = 3 × 5 = 15 Probability = 15 / 56

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Asked 12 days ago|2/23/2026 9:23:18 AM

Updated 12 days ago|2/23/2026 10:01:22 AM

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cruz30

Total ways = C(8,3) = 56
Favorable = C(3,2) × C(5,1) = 3 × 5 = 15
Probability = 15 / 56

Added 12 days ago|2/23/2026 10:00:29 AM

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Salas1987

by C(8,3) = 8! / (3! * 5!) = (8 * 7 * 6) / (3 * 2 * 1) = 56.

C(5,1) = 5! / (1! * 4!) = 5.
So, the number of ways to draw exactly 2 red balls and 1 blue ball is C(3,2) * C(5,1) = 3 * 5 = 15.
The probability is the number of favorable outcomes divided by the total number of outcomes: 15 / 56.

Added 12 days ago|2/23/2026 10:01:22 AM

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