Solve 4(x - 3) - 2(x - 1) > 0. {x | x -5} {x | x > 5} {x | x < 5}
Question
Updated 3/28/2014 1:06:21 PM
Flagged by andrewpallarca [3/28/2014 1:06:21 PM]
Original conversation
User: Solve 4(x - 3) - 2(x - 1) > 0. {x | x < -5} {x | x > -5} {x | x > 5} {x | x < 5}

Question
Updated 3/28/2014 1:06:21 PM
Flagged by andrewpallarca [3/28/2014 1:06:21 PM]
Rating
3
4(x - 3) - 2(x - 1) > 0

(4x - 12) - (2x + 2) > 0

2x - 10 > 0

2x > 0 + 10

2x > 10

x > 10/2

x > 5

Questions asked by the same visitor
Given the system of equations, what is the solution? 5x - 4y = 7 x = 5 - y
Weegy: {(61/23, 36/23)} (More)
Question
Updated 9/15/2014 7:46:29 AM
The solution for 5x - 4y = 7, x = 5 - y is x = 3, y =2 ,which is not in the options .
Put x = 5 - y in 1th equation
5x -4y = 7
5( 5 - y) - 4y = 7
25 - 9y = 7
-9y = -18
y = 2

x = 5 - y
x = 5-2
x = 3
Confirmed by andrewpallarca [9/15/2014 7:46:21 AM], Rated good by andrewpallarca
The system shown has _____ solution(s). y = x + 1 2y - x = 6 no one infinite
Weegy: y=x+12_y-x=2... Replace all occurrences of y with the solution found by solving the last equation for y. [ In this case, the value substituted is x+12. y=x+12_(x+12)-x=2.. Remove the parentheses around the expression x+12. y=x+12_x+12-x=2... Since x and -x are like terms, add -x to x to get 0. y=x+12_0+12=2... Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression. y=x+12_12=2... Since 12 is not equal to 2, there are no solutions. The system shown has no Solutions. ] (More)
Question
Updated 3/30/2014 9:46:19 PM
y = x + 1, the first equation
2y - x = 6, the second equation
Replace y in the second equation with the first one we get:
2(x + 1) - x = 6
solve the equation we get x = 4
so, y = 4 + 1 = 5
The system y = x +1, 2y - x = 6 has one solution (4, 5)
Confirmed by jeifunk [3/30/2014 9:52:50 PM]
27,884,327
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