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Steel rod, L = 1.5 m, d = 12 mm, load 80 kN. Stress?
Stress = Force / Area. Area = (d/2)² 113.1 mm². Stress = 707.3 MPa.
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Asked 30 days ago|1/14/2026 12:37:56 PM
Updated 30 days ago|1/14/2026 1:14:49 PM
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Steel rod, L = 1.5 m, d = 12 mm, load 80 kN. Stress?
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Flora1988
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Added 30 days ago|1/14/2026 1:14:32 PM
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Flora1988
[1/14/2026 1:14:54 PM]
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cruz30
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Added 30 days ago|1/14/2026 1:14:42 PM
This answer has been added to the Weegy Knowledgebase
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cruz30
[1/14/2026 1:14:50 PM]
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Flora1988
Stress = Force / Area. Area = (d/2)² 113.1 mm². Stress = 707.3 MPa.
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Added 30 days ago|1/14/2026 1:14:49 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
Calculate the molarity of a solution prepared by dissolving 9.8 g of H SO in 500 mL of water.
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Question
Not Answered
Updated 31 days ago|1/13/2026 7:33:30 AM
1 Answer/Comment
3
cruz30
Formula:
Molarity, C = n / V
where n = m / M
Calculation:
n = 9.8 / 98 = 0.1 mol
C = 0.1 / 0.5 = 0.2 M
Answer: 0.2 M
Added 31 days ago|1/13/2026 7:33:30 AM
This answer has been confirmed as correct and helpful.
Determine the oxidation number of Mn in KMnO .
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Question
Not Answered
Updated 31 days ago|1/13/2026 7:33:00 AM
1 Answer/Comment
3
cruz30
Given:
Compound: KMnO4
Assign known oxidation numbers
K = +1
O = -2
Let Mn = x
Charge of compound = 0 (neutral)
Write equation
(+1) + x + 4(-2) = 0
1 + x - 8 = 0
x - 7 = 0
Solve for x
x = +7
Answer: Oxidation number of Mn = +7
Added 31 days ago|1/13/2026 7:33:00 AM
This answer has been confirmed as correct and helpful.
Find the pH of a solution with hydroxide ion concentration 1×10 ³ M.
Weegy:
The pH scale measures the concentration of hydroxide ions. FALSE.
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Question
Updated 31 days ago|1/13/2026 7:34:17 AM
1 Answer/Comment
3
cruz30
Given:
[OH ] = 1 × 10 ³ M
Use relation between pH and pOH
pOH = -log[OH ]
Calculation of pOH:
pOH = -log(1 × 10 ³)
pOH = 3
Use relation pH + pOH = 14
pH = 14 - pOH
pH = 14 - 3
pH = 11
Answer: 11
Added 31 days ago|1/13/2026 7:34:11 AM
This answer has been confirmed as correct and helpful.
Calculate the number of molecules in 11 g of CO
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Question
Not Answered
Updated 31 days ago|1/13/2026 7:31:53 AM
1 Answer/Comment
3
cruz30
Formula:
Number of moles, n = m / M
Number of molecules = n × NA
Calculation:
n = 11 / 28 = 0.39286 mol
Number of molecules = 0.39286 × 6.022 × 10²³
= 2.37 × 10²³ molecules
Answer: = 2.37 × 10²³ molecules
Added 31 days ago|1/13/2026 7:31:53 AM
This answer has been confirmed as correct and helpful.
Identify the hybridization of carbon in C H .
Weegy:
Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties.
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Question
Updated 31 days ago|1/13/2026 7:35:00 AM
1 Answer/Comment
3
cruz30
Given:
Molecule: CH4 (methane)
Determine bonding
- Carbon forms 4 sigma bonds with 4 hydrogen atoms.
- No lone pairs on carbon.
Determine hybridization
- Number of sigma bonds + lone pairs on carbon = 4 sp³ hybridization
Answer: sp³
Added 31 days ago|1/13/2026 7:34:55 AM
This answer has been confirmed as correct and helpful.
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