Solve the quadratic equation x2 - 56 = 10x by factoring. A. {4, 14} B. {-14, 4} C. {-14, -4} D. {-4, 14}
x^2 - 56 = 10x; x^2 - 10x - 56 = 0; (x + 4)(x - 14) = 0 (x + 4) = 0; x = -4; (x - 14) = 0; x = 14 the solution set is {-4, 14}
Question
Asked 8/5/2013 1:04:17 AM
Updated 6/27/2014 7:35:20 PM
Rating
3
x^2 - 56 = 10x;

x^2 - 10x - 56 = 0;

(x + 4)(x - 14) = 0
(x + 4) = 0; x = -4;
(x - 14) = 0; x = 14

the solution set is {-4, 14}

Added 6/27/2014 7:35:20 PM
This answer has been confirmed as correct and helpful.

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Solve the quadratic equation 12x^2 - 3x - 9 = 0 by factoring.
Weegy: (3x-2) squared is 9x^2 - 12x + 4. (More)
Question
Updated 6/27/2014 1:07:27 PM
12x^2 - 3x - 9 = 0
12x^2 - 3x - 9 = 3(4x + 3)(x - 1)

3(4x + 3) = 0;
12x + 9 = 0;
12x = 0 - 9;
x = -9/12 = -3/4

(x - 1) = 0;
x = 1

x = {-3/4, 1}
Added 6/27/2014 1:07:25 PM
This answer has been confirmed as correct and helpful.
Use the quadratic formula to solve 5x2 - 2x - 3 = 0
Weegy: x = -14/11 User: Solve: (x + 1)2 = 9 A. -2, 4 B. 2, -4 C. 2, 4 D. 1, -4 (More)
Question
Updated 6/27/2014 1:15:56 PM
5x^2 - 2x - 3 = 0
5x^2 - 2x - 3 = (5x + 3)(x - 1)

(5x + 3) = 0;
5x = -3;
x = -3/5

(x - 1) = 0;
x = 1

x = (-3/5, 1)
Added 6/27/2014 1:10:42 PM
This answer has been confirmed as correct and helpful.
(x + 1)^2 = 9;

x^2 + 2x + 1 = 9;

x^2 + 2x + 1 - 9 = 0;

x^2 + 2x - 8 = 0

x^2 + 2x - 8 = (x + 4)(x - 2)

(x + 4) = 0; x = -4;
(x - 2) = 0; x = 2

x = -4 or x = 2
Added 6/27/2014 1:15:56 PM
This answer has been confirmed as correct and helpful.
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