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Solve 3x 2 + 2 = 11 - x 2 {±3/2} {± 3} {}
Question
Asked 11/14/2014 8:42:35 AM
Updated 11/15/2014 5:34:33 AM
2 Answers/Comments
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Flagged by janezeshun [11/15/2014 5:33:56 AM]
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User: Solve 3x 2 + 2 = 11 - x 2 {±3/2} {± 3} {}

Weegy: 3x - 5 < 4

3x < 5+4

3x <9

3x < 3



User: Find the product and fill in the blanks to write in standard complex number form. (2 + 4i)(7 - 3i) = a0 + a1 i

Question
Asked 11/14/2014 8:42:35 AM
Updated 11/15/2014 5:34:33 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by janezeshun [11/15/2014 5:33:56 AM]
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The solution for 3x^2 + 2 = 11 - x^2 is {±3/2} .
3x^2 + 2 = 11 - x^2
3x^2 + x^2 = 11 - 2
4x^2 = 9
x^2 = 9/4
x = 3/2 , or x = -3/2
Added 11/15/2014 5:33:54 AM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/15/2014 12:24:21 PM]
5
(2 + 4i)(7 - 3i)
= 14 + 28i - 6i - 12i^2
= -12i^2 + 22i + 12
Added 11/15/2014 5:34:33 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/15/2014 5:37:55 AM]
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Questions asked by the same visitor
Find the center of the following equation. x 2 + y 2 + 8 x - 6 y - 15 = 0
Question
Updated 11/10/2014 11:24:59 PM
1 Answer/Comment
x^2 + y^2 + 8x - 6y - 15 = 0
(x + 4)^2 - 16 + (y - 3)^2 - 9 - 15 = 0
(x + 4)^2 + (y - 3)^2 = 40
(-4 , 3) is the center of equation.:x^2 + y^2 + 8x - 6y - 15 = 0 .
Added 11/10/2014 11:24:59 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/11/2014 12:51:23 AM]
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Question
Not Answered
Updated 11/11/2014 7:37:43 AM
2 Answers/Comments
(3x - 1)^2 = 5
3x - 1 = ± sqrt 5
3x = 1 ± sqrt 5
x = (1 ± sqrt 5)/3
Added 11/11/2014 7:35:35 AM
This answer has been confirmed as correct and helpful.
x^2 + 5x + 1 = 0
a = 1, b = 5, c = 1
discriminant = b^2 - 4ac = 25 - 4 = 21
x = (-5 ± sqrt 21)/2
Added 11/11/2014 7:37:43 AM
This answer has been confirmed as correct and helpful.
The radius of the circle whose equation is (x + 4)² + (y - 2)² = 36 is 36 18 6
Weegy: If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is 6. User: The distance between the points (5, -2) and (-7, 3) is 5 29 13 (More)
Question
Updated 11/12/2014 10:56:02 PM
1 Answer/Comment
The distance between the points (5, -2) and (-7, 3) is 13 .
Let the distance is d
d^2 = (-7-5)^2 + {3 - (-2)}^2
d^2 = 144 + 25
d^2 = 169
d = 13
Added 11/12/2014 10:45:36 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/12/2014 10:56:22 PM], Rated good by jeifunk
Solve (x + 2)(2x + 3) = 6 {-2, -3/2} {-7/2, 0} {0}
Question
Not Answered
Updated 11/15/2014 2:38:32 PM
1 Answer/Comment
The solution set for (x + 2)(2x + 3) = 6 is {-7/2, 0}.

(x + 2)(2x + 3) = 6;
2x^2 +3x + 4x + 6 = 6;
2x^2 + 7x + 6 - 6 = 0;
2x^2 + 7x = 0;
x(2x + 7) = 0;
x = 0;
2x + 7 = 0; 2x = -7; x = -7/2
Added 11/15/2014 2:38:32 PM
This answer has been confirmed as correct and helpful.
What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)? (-10.5, 5) (-10.5, 7) (-2.5, 7)
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Question
Not Answered
Updated 11/15/2014 2:39:44 PM
1 Answer/Comment
The equation of a circle whose center is at the origin and whose radius is 16 is: x^2 + y^2 = 256
Added 11/8/2014 4:10:30 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [11/15/2014 2:39:54 PM]
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