A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. What is the magnitude of the current flowing through the first device? A. 13.32 A B. 10 A C. 8 A D. 3.33 A
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A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. 3.33 A is the magnitude of the current flowing through the first device. Solution: 40V = V1 =V2 Since V =IR I1 = V1/R1 I1 = (40V)/(12 ohms) I1 = 3.334 A.
Question
Updated 10 days ago|6/11/2021 1:15:55 PM
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A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. 3.33 A is the magnitude of the current flowing through the first device. Solution: 40V = V1 =V2 Since V =IR I1 = V1/R1 I1 = (40V)/(12 ohms) I1 = 3.334 A.
Added 10 days ago|6/11/2021 1:15:55 PM

Questions asked by the same visitor
A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. What is the magnitude of the current flowing through the first device? A. 13.32 A B. 10 A C. 8 A D. 3.33 A
Question
Updated 181 days ago|12/22/2020 3:31:42 PM
A complete circuit contains two parallel-connected devices and a generator for providing the electromotive force. The resistance of the first device is 12 ohms, the resistance of the second device is 4 ohms, and the voltage developed by the generator is 40 V. 3.33 A is the magnitude of the current flowing through the first device. Solution: 40V = V1 =V2 Since V =IR I1 = V1/R1 I1 = (40V)/(12 ohms) I1 = 3.334 A.

Added 181 days ago|12/22/2020 3:31:42 PM
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