2p^2-3p-2=0
2p^2 - 3p - 2 = 0 (2p + 1)(p - 2) = 0; 2p + 1 = 0; 2p = -1; p = -1/2 p - 2 = 0; p = 2 p = {-1/2, 2)
Question
Updated 1/6/2016 8:22:43 AM
Rating
3
2p^2 - 3p - 2 = 0

(2p + 1)(p - 2) = 0;

2p + 1 = 0;
2p = -1;
p = -1/2

p - 2 = 0;
p = 2

p = {-1/2, 2)
Confirmed by Andrew. [1/6/2016 11:45:57 PM]

Questions asked by the same visitor
-2x^2+x=0
Question
Updated 1/6/2016 8:24:22 AM

-2x^2+x=0

-x(2x - 1) = 0;

-x = 0;
x = 0

2x - 1 = 0;
2x = 1;
x = 1/2;

x = {0, 1/2}
Confirmed by jeifunk [1/6/2016 8:25:52 AM]
(3-5i)(2+9i)+(7+2i)(7-2i)
Question
Updated 1/6/2016 8:28:52 AM
(3-5i)(2+9i)+(7+2i)(7-2i) = 104 + 17i
27,651,955
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