A current of 9 A flows through an electric device with a resistance of 43 Î©. What must be the applied voltage in this particular circuit? A. 387 V B. 387 A C. 4.8 A D. 4.8 V

A current of 9 amps flows through an electric device with a resistance of 43 ohm. The applied voltage in the particular circuit is 387 volts. V =IR ; V = 9 * 43 = 387 volts.

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Asked 4/9/2019 7:18:52 AM

Updated 45 days ago|9/4/2020 3:05:48 PM

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A current of 9 amps flows through an electric device with a resistance of 43 ohm. The applied voltage in the particular circuit is 387 volts.

V =IR ; V = 9 * 43 = 387 volts.

V =IR ; V = 9 * 43 = 387 volts.

Added 45 days ago|9/4/2020 3:05:48 PM

This answer has been confirmed as correct and helpful.

Why did the India Act in 1937 fail? A. The common people didn't support it. B. Hindus feared the Muslim majority. C. Muslims feared that Hindus would dominate the legislature. D. Gandhi opposed the Act. **Weegy:** The India Act in 1937 failed because: Muslims feared that Hindus would dominate the legislature. (More)

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Updated 4/8/2019 6:30:35 PM

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An object with a mass of 78 kilograms is lifted through a height of 6 meters. How much work is done? A. 47.75 J B. 4,586.4 J C. 764.4 J D. 468 J

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Updated 89 days ago|7/22/2020 10:33:28 PM

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An object with a mass of 78 kilograms is lifted through a height of 6 meters. The work done is 4,586.4 J.

Solution:

Work done = mgh

Work done = 78 * 9.8 * 6

Work done = 4,586.4 J. (answer)

Solution:

Work done = mgh

Work done = 78 * 9.8 * 6

Work done = 4,586.4 J. (answer)

Added 89 days ago|7/22/2020 10:33:28 PM

This answer has been confirmed as correct and helpful.

. A body moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. How far does the body move in 5 seconds? A. 260 m B. 196 m C. 162.5 m D. 137.5 m

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Updated 142 days ago|5/31/2020 11:50:33 AM

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A body moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. the body moves 137.5 meters in 5 seconds.

Solution:

s = ut + 1/2 at^2; s = 20 m/s (5 sec) + (1/2) (3 m/s^2) (5 sec)^2

s =100 m + (1.5 m/s^2) (25 s^2)

s = 100 m + 37.5 m

s = 137.5 meters. (answer)

Solution:

s = ut + 1/2 at^2; s = 20 m/s (5 sec) + (1/2) (3 m/s^2) (5 sec)^2

s =100 m + (1.5 m/s^2) (25 s^2)

s = 100 m + 37.5 m

s = 137.5 meters. (answer)

Added 142 days ago|5/31/2020 11:50:33 AM

This answer has been confirmed as correct and helpful.

Imagine that a tank is filled with water. The height of the liquid column is 7 meters and the area is 1.5 square meters (m2). What's the force of gravity acting on the column of water? A. 73,500 N B. 102,900 N C. 110,700 N D. 68,600 N

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Updated 119 days ago|6/22/2020 4:48:10 PM

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Imagine that a tank is filled with water. The height of the liquid column is 7 meters and the area is 1.5 square meters (m2). The force of gravity acting on the column of water is 102,900 N. Solution: The volume of water is (1.5 m² x 7 m) = 10.5 m³; 10.5 m³ = 10,500 liters; Weight of the water = (10,500 kg) x (9.8 m/s²) = 102,900 newtons.

Added 119 days ago|6/22/2020 4:48:10 PM

This answer has been confirmed as correct and helpful.

A temperature of 200 F is equivalent to approximately A. 232 C. B. 37.8 C. C. 93.3 C. D. 840 C. **Weegy:** A temperature of 200 F is equivalent to approximately 93.3 C.
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Updated 5/9/2019 2:05:04 PM

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