The number of moles in 22 g of CO is:

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The number of moles in 22 g of CO is: 0.785 moles.

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Asked 32 days ago|1/12/2026 7:36:29 AM

Updated 32 days ago|1/12/2026 7:59:55 AM

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Greygrey

The number of moles in 22 g of CO is: 0.785 moles.

Added 32 days ago|1/12/2026 7:58:37 AM

This answer has been confirmed as correct and helpful.

Flora1988

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Added 32 days ago|1/12/2026 7:59:55 AM

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Deleted by Flora1988 [1/12/2026 8:00:01 AM]

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Torque T=500 Nm, radius 0.25 m. Force?

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Updated 32 days ago|1/12/2026 7:46:43 AM

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cruz30

Solve for F
F = T / r
F = 500 / 0.25
F = 2000 N
Answer:
The force is 2000 N

Added 32 days ago|1/12/2026 7:46:43 AM

This answer has been confirmed as correct and helpful.

Moment of inertia for rectangle b=0.3 m, h=0.5 m about base?

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Updated 32 days ago|1/12/2026 7:52:45 AM

1 Answer/Comment

cruz30

Formula: I_base = (b × h³) / 3
Plug in the values
I_base = (0.3 × 0.5³) / 3
0.5³ = 0.125
I_base = (0.3 × 0.125) / 3
I_base = 0.0375 / 3 = 0.0125 m
Answer:
Moment of inertia about the base = 0.0125 m

Added 32 days ago|1/12/2026 7:52:45 AM

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Efficiency = P_out/P_in. Input 2 kW, output 1.7 kW. ?

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Updated 32 days ago|1/12/2026 7:45:28 AM

1 Answer/Comment

cruz30

Plug in the values
Efficiency = 1.7 / 2
Efficiency = 0.85
Convert to percentage
Efficiency = 0.85 × 100% = 85%
Answer:
The efficiency is 85%

Added 32 days ago|1/12/2026 7:45:28 AM

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Maximum bending stress =? M=50 kNm, I=400×10 mm , y=200 mm

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Updated 32 days ago|1/12/2026 7:52:06 AM

1 Answer/Comment

cruz30

Formula: _max = M × y / I
Plug in the values
_max = (50,000 × 0.2) / 0.0004
_max = 10,000 / 0.0004
_max = 25,000,000 Pa = 25 MPa
Answer:
Maximum bending stress = 25 MPa

Added 32 days ago|1/12/2026 7:52:06 AM

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Power of motor lifting 250 kg, h=15 m, t=10 s?

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Updated 32 days ago|1/12/2026 7:48:02 AM

1 Answer/Comment

cruz30

Calculate work done
W = m × g × h
W = 250 × 9.8 × 15
W = 36,750 J
Calculate power
P = W / t
P = 36,750 / 10
P = 3,675 W
P = 3.68 kW
Answer:
The motor’s power is approximately 3.68 kW

Added 32 days ago|1/12/2026 7:48:02 AM

This answer has been confirmed as correct and helpful.

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