Question and answer
Find molality of solution with 5 g NaCl in 120 g water.
Na (22.99 g/mol) + Cl (35.45 g/mol) = 58.44 g/mol. Moles of NaCl = 5 g / 58.44 g/mol = 0.08556 mol. Mass of water in kg = 120 g / 1000 g/kg = 0.120 kg. Molality = moles of solute / mass of solvent (kg) = 0.08556 mol / 0.120 kg = 0.713 mol/kg.
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Asked 34 days ago|2/1/2026 10:45:42 AM
Updated 34 days ago|2/1/2026 8:14:11 PM
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Added 34 days ago|2/1/2026 8:12:35 PM
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Na (22.99 g/mol) + Cl (35.45 g/mol) = 58.44 g/mol.

Moles of NaCl = 5 g / 58.44 g/mol = 0.08556 mol.

Mass of water in kg = 120 g / 1000 g/kg = 0.120 kg.

Molality = moles of solute / mass of solvent (kg) = 0.08556 mol / 0.120 kg = 0.713 mol/kg.
Added 34 days ago|2/1/2026 8:14:11 PM
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Questions asked by the same visitor
A 5 F and 12 F capacitor are in series across 200 V. Find charge on each
Question
Not Answered
Updated 33 days ago|2/2/2026 6:00:11 AM
1 Answer/Comment
Given:
C = 5 F, C = 12 F, V = 200 V
Series capacitance:
1/C_eq = 1/C + 1/C
1/C_eq = 1/5 + 1/12
1/C_eq = 0.2 + 0.0833 = 0.2833
C_eq 3.53 F
Charge Q = C_eq × V
Q = 3.53 × 200 = 706 C
Voltage across each capacitor:
V = Q / C = 706 / 5 = 141.2 V
V = Q / C = 706 / 12 = 58.8 V
Answer:
Charge on each: 706 C
Voltages: V = 141.2 V, V = 58.8 V
Added 33 days ago|2/2/2026 6:00:11 AM
This answer has been confirmed as correct and helpful.
A stone is dropped from 85 m. Find velocity just before impact.
Question
Not Answered
Updated 33 days ago|2/2/2026 5:57:27 AM
1 Answer/Comment
Given:
h = 85 m
g = 9.8 m/s²
u = 0 m/s
v² = u² + 2 g h
v² = 0 + 2 × 9.8 × 85
v² = 1666
v = sqrt1666
v = 40.82 m/s
Answer: 40.8 m/s
Added 33 days ago|2/2/2026 5:57:27 AM
This answer has been confirmed as correct and helpful.
A mirror forms image 30 cm from mirror for object at 60 cm. Find focal length.
Question
Not Answered
Updated 33 days ago|2/2/2026 5:49:57 AM
2 Answers/Comments
Given:
Object distance u = 60 cm
Image distance v = 30 cm
Mirror formula:
1/f = 1/u + 1/v
1/f = 1/60 + 1/30
1/f = (1 + 2)/60
1/f = 3/60
1/f = 1/20
f = 20 cm
Answer: 20 cm
Added 33 days ago|2/2/2026 5:48:07 AM
This answer has been confirmed as correct and helpful.
[Deleted]
Added 33 days ago|2/2/2026 5:49:57 AM
Deleted by Salas1987 [2/2/2026 5:50:04 AM]
A car of mass 1350 kg accelerates from 12 m/s to 28 m/s in 9 s. Determine average force.
Question
Not Answered
Updated 33 days ago|2/2/2026 6:05:20 AM
1 Answer/Comment
Given:
m = 1350 kg
u = 12 m/s
v = 28 m/s
t = 9 s
Acceleration a = (v - u) / t
a = (28 - 12) / 9
a = 16 / 9 = 1.778 m/s²
Force F = m × a
F = 1350 × 1.778
F = 2400 N
Answer: 2400 N
Added 33 days ago|2/2/2026 6:05:20 AM
This answer has been confirmed as correct and helpful.
Find boiling point elevation for 0.9 mol solute in 1.2 kg water, Kb=0.52.
Question
Not Answered
Updated 33 days ago|2/2/2026 5:51:46 AM
1 Answer/Comment
Given:
n = 0.9 mol
m_solvent = 1.2 kg
Kb = 0.52 °C·kg/mol
Tb = Kb × (n / m_solvent)
Tb = 0.52 × (0.9 / 1.2)
Tb = 0.52 × 0.75
Tb = 0.39 °C
Answer: 0.39 °C
Added 33 days ago|2/2/2026 5:51:46 AM
This answer has been confirmed as correct and helpful.
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