3
Given system:
y = x^2 - 2x - 15
y = 8x - 40
Set the equations equal
x^2 - 2x - 15 = 8x - 40
x^2 - 2x - 15 - 8x + 40 = 0
x^2 - 10x + 25 = 0
Factor the quadratic
(x - 5)^2 = 0
x = 5
Solve for y
y = 8x - 40
y = 8(5) - 40 = 0
Solution set: (5, 0)
Answer: (5, 0)
Added 9 days ago|12/3/2025 10:52:19 AM
This answer has been confirmed as correct and helpful.