factors of 4b^2 - 16 ?
4b^2 - 16 =4[(b)^2 - (2)^2] = 4(b +2) (b - 2)
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Asked 2/2/2018 10:15:30 AM
Updated 2/2/2018 10:50:38 AM
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jeifunk [2/2/2018 10:50:37 AM], Confirmed by
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