Question and answer
Evaluate the following expression. (-6)^-2
(-6)^-2 = 1/(-6)^2 = 1/36
Question
Asked 5/4/2015 10:36:43 AM
Updated 5/4/2015 12:54:35 PM
1 Answer/Comment
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(-6)^-2 = 1/(-6)^2 = 1/36
Added 5/4/2015 12:54:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [5/6/2015 2:24:05 PM]
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Questions asked by the same visitor
Simplify (x 2 y) 3.
Question
Not Answered
Updated 4/27/2015 6:36:31 PM
1 Answer/Comment
(x^2y)^3
= x^6y^3
Added 4/27/2015 6:36:31 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [4/27/2015 6:49:41 PM]
Simplify. (-4·3·2)2
Weegy: (-4 * 3 * 2)^2 = (-24)^2 = 576 User: Simplfy. (a 2 b 3)4 Weegy: (a^2 b^3)^4 = a^8 b^12 User: Simplify. (-7p)3 Weegy: (-7p)^3 = (-7p)(-7p)(-7p) = (49p^2)(-7p) = -343p^3 User: The expression (2x2)3 is equivalent to _____. (More)
Question
Not Answered
Updated 6/6/2015 11:49:44 AM
1 Answer/Comment
The expression (2x^2)^3 is equivalent to 8x^6.
Added 4/27/2015 9:25:19 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [6/6/2015 2:33:13 PM]
Evaluate (x + y )^0 for x = –3 and y = 5. User: Simplify. n^6 • n^5 ÷ n^4 • n^3 ÷ n^2 • n
Question
Updated 4/27/2015 12:02:13 PM
2 Answers/Comments
(x + y )^0 for x = –3 and y = 5;
(-3 + 5)^0
= 2^0
= 1
Added 4/27/2015 12:02:02 PM
This answer has been confirmed as correct and helpful.
n^6 • n^5 ÷ n^4 • n^3 ÷ n^2 • n
= n^11 ÷ n^4 • n^3 ÷ n^2 • n
= n^7 • n^3 ÷ n^2 • n
= n^10 ÷ n^2 • n
= n^8 • n
= n^9
Added 4/27/2015 12:02:13 PM
This answer has been confirmed as correct and helpful.
(2n^3 + 4n^2 - 7) + (-n^3 + 8n - 9)
Weegy: (2n^3 + 4n^2 - 7) + (-n^3 + 8n - 9) = 2n^3 + 4n^2 - 7 - n^3 + 8n - 9 = n^3 + 4n^2 + 8n - 16 (final answer) (More)
Question
Expert Answered
Updated 5/8/2015 2:31:50 PM
0 Answers/Comments
Find the product. 5x^2 · 2y^2
Weegy: 5x^2 * 2y^2 = 10x^2y^2 User: Find the product. x^5 · x^4 · x^3 (More)
Question
Updated 4/28/2015 3:09:20 AM
1 Answer/Comment
x^5*x^4*x^3
=x^9*x^3
=x^12
Added 4/27/2015 8:06:54 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [4/27/2015 8:14:20 PM]
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