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f = 1/(2 n sqrt(LC)) = C = 1/(4 n² f² L)
C = 1/(4n ² × 50² × 0.2)
C = 3.18×10 F
Added 25 days ago|2/10/2026 1:40:32 PM
This answer has been confirmed as correct and helpful.
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f = 1 / (2 * * (L * C))
C = 1 / ((2 * * f)^2 * L).
C = 1 / ((2 * * 50)^2 * 0.2) = 1 / ((314.159265359)^2 * 0.2) = 1 / (98696.0440109 * 0.2) = 1 / 19739.2088022 = 0.0000506605 F.
Converting this to microfarads, C = 50.66 µF.
Therefore, the capacitance needed is approximately 50.66 µF.
Added 25 days ago|2/10/2026 1:51:56 PM