Question and answer
Find the product. (n 3)2 · (n 5)4
Question
Asked 7/4/2016 6:54:39 PM
Updated 7/4/2016 9:17:57 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by Venen [7/4/2016 9:16:47 PM]
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User: Find the product. (n 3)2 · (n 5)4

Weegy: (n^9)*(n^20)
elgour|Points 10|

User: (n^9)*(n^20)

Question
Asked 7/4/2016 6:54:39 PM
Updated 7/4/2016 9:17:57 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by Venen [7/4/2016 9:16:47 PM]
New answers
Rating
3
(n^3)^2 · (n^5)^4;
= n^6*n^20;
= n^26
Added 7/4/2016 9:17:38 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/5/2016 8:47:22 AM]
3
(n^9)*(n^20)
= n^29
Added 7/4/2016 9:17:57 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/5/2016 8:47:26 AM]
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Questions asked by the same visitor
Fully factor x(2x + 3) + (x - 3)(x - 4)
Question
Updated 7/1/2016 9:23:01 AM
1 Answer/Comment
x(2x + 3) + (x - 3)(x - 4) = 3x^2 - 4x + 12
Added 7/1/2016 9:22:58 AM
This answer has been confirmed as correct and helpful.
5^-3
Question
Updated 7/2/2016 10:43:20 AM
1 Answer/Comment
5^-3 = 0.008
Added 7/2/2016 10:29:39 AM
This answer has been confirmed as correct and helpful.
Confirmed by vchutkan [7/2/2016 10:43:18 AM]
7,529,536^1/3
Question
Updated 7/4/2016 1:46:13 AM
1 Answer/Comment
7,529,536^1/3
= 7,529,536/3
= 2509845.33
Added 7/4/2016 1:46:13 AM
This answer has been confirmed as correct and helpful.
7(-a^2)^2*(-b^3)
Question
Updated 7/5/2016 2:57:48 AM
1 Answer/Comment
7(-a^2)^2*(-b^3)
= 7a^4*(-b^3)
= -7a^4b^3
Added 7/5/2016 2:57:48 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/5/2016 6:20:26 AM]
Factor k2 - 81.
Weegy: k^2 - 81 = (k - 9)(k + 9) User: Factor k2 - 17k + 16. Weegy: k^2 - 17k + 16 = (k - 1)(k - 16) User: Factor 64a2 - 48a + 9. Weegy: 64a2 - 48a + 9 = (8a - 3)(8a - 3) = (8a - 3)^2 (More)
Question
Updated 7/1/2016 9:25:57 AM
0 Answers/Comments
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