What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3 .
3x - y - 7 = 0
x - 3y + 7 = 0
x - 3y - 7 = 0

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3 .
3x - y - 7 = 0
x - 3y + 7 = 0
x - 3y - 7 = 0

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3 . 3x - y - 7 = 0 x - 3y + 7 = 0 x - 3y - 7 = 0

Original conversation

User: What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3 .
3x - y - 7 = 0
x - 3y + 7 = 0
x - 3y - 7 = 0

Weegy: The equation of the line that passes through (5,0) and has a slope of -2/3 is y=-2/3x+10/3 andrewpallarca|Points 34826|

x + y - 4 = 0 x - y = 0 Adding up the above equations we get: 2x - 4 = 0 x = 4/2 = 2 y = x = 2 The solution for the system of equations x + y - 4 = 0, x - y = 0 is (2, 2) which lies in quadrant I.

Added 5/3/2014 7:42:06 PM

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