Write the quadratic equation in general form and then choose the value of "b." (2x - 1)(x + 6) = 0
Question
Updated 4/10/2014 8:51:34 PM
Flagged by yeswey [4/10/2014 8:50:36 PM]
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Original conversation
User: Write the quadratic equation in general form and then choose the value of "b." (2x - 1)(x + 6) = 0

User: Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?

Question
Updated 4/10/2014 8:51:34 PM
Flagged by yeswey [4/10/2014 8:50:36 PM]
Rating
3
(2x - 1)(x + 6) = 0
2x^2 + 12x - x - 6 = 0
2x^2 + 11x - 6 = 0 which is the standard form.
a = 2, b = 11, c = -6
The value of b is 11.
Confirmed by jeifunk [4/10/2014 8:52:24 PM]

Questions asked by the same visitor
Find the distance between the points (2, 8) and (-1, 9).
Weegy: -1/8 *1/2 = -1/16 User: Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9). Weegy: using midpoint formula mid point = (X2+X1)/2 ; (Y2+Y1)/2 (-2+5)/2 ; (-9+5)/2 = (7/2,-2) the mid point is (3/2,-2) User: y(y + 4) - y 2 = 6 is a quadratic equation. Weegy: y(y + 4) - y^2 = 6 y^2 + 4y - y^2 = 0 4y = 0, y= 0 whose gragh is y axle. Thus, y(y + 4) - y^2 = 6 is a quadratic equation. This is false. User: Which of the following describes the translation of the graph of y = x2 to obtain the graph of y = -x2 + 3? (More)
Question
Updated 4/10/2014 9:03:49 PM
The distance between the points (2, 8) and (-1, 9) is sqrt 10.
Confirmed by jeifunk [4/10/2014 8:59:53 PM]
The midpoint of the line segment whose endpoints are (-2, 5) and (6, -9) is (2, -2).
Confirmed by jeifunk [4/10/2014 9:15:53 PM]
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