Weegy: ab + 4 + a + 4b
User: Factor this expression completely and then place the factors in the proper location on the grid. Note: Place factors alphabetically in the grid!
mr + ns - nr - ms
Weegy: mr - ms - nr + ns
User: Factor this expression completely and then place the factors in the proper location on the grid. Note: Place factors alphabetically in the grid!
ab + 2a + 3b + 6
Weegy: mr - ms - nr + ns
= m (r - s) - n(r - s)
= (r -s)(m - n)
User: Factor this expression completely and then place the factors in the proper location on the grid. Note: Place factors alphabetically in the grid!
ab + 2a + 3b + 6
Weegy: mr - ms - nr + ns
= m (r - s) - n(r - s)
= (r -s)(m - n)
(More) 3
To factor the expression ab + 2a + 3b + 6 completely, let's rearrange the terms and look for common factors:
ab + 2a + 3b + 6
Rearranging the terms:
2a + ab + 3b + 6
Now let's factor by grouping:
Group the terms:
(2a + ab) + (3b + 6)
In the first group, we can factor out "a":
a(2 + b)
In the second group, we can factor out "3":
3(b + 2)
Putting it all together, the factored form of the expression is:
a(2 + b) + 3(b + 2)
Now we can place the factors alphabetically in the grid:
| a b |
| 2 + b |
| b + 2 |
| 2 + b |
The factors are placed in the respective cells of the grid.
Added 7/11/2023 12:31:55 AM
This answer has been confirmed as correct and helpful.
3
To factor the expression mr + ns - nr - ms completely, let's rearrange the terms and look for common factors:
mr + ns - nr - ms
Rearranging the terms:
mr - nr + ns - ms
Now let's factor by grouping:
Group the terms:
(mr - nr) + (ns - ms)
In the first group, we can factor out "r":
r(m - n)
In the second group, we can factor out "s":
s(n - m)
Putting it all together, the factored form of the expression is:
r(m - n) + s(n - m)
Now we can place the factors alphabetically in the grid:
| m n |
| r - n |
| n - m |
| r - s |
The factors are placed in the respective cells of the grid.
Added 7/11/2023 12:33:31 AM
This answer has been confirmed as correct and helpful.
