12x^-4 y^2/3x^2 y^-4 Simplify the expression
12x^-4 y^2/3x^2 y^-4 = 4x^-4y^2/x^2y^-4 = (4y^2/x^4)/(x^2/y^4) = 4y^2/x^4*y^4/x^2 = 4y^6/x^6
Question
Updated 3/10/2015 5:42:54 AM
Rating
3
12x^-4 y^2/3x^2 y^-4
= 4x^-4y^2/x^2y^-4
= (4y^2/x^4)/(x^2/y^4)
= 4y^2/x^4*y^4/x^2
= 4y^6/x^6
Confirmed by jeifunk [3/10/2015 5:56:33 AM]

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